Question

我需要从这个对象数组中提取数据

{
    "data": [
        {
            "id": "136104923104306",
            "from": {
                "name": "GetWith.It",
                "category": "Website",
                "id": "136132969751208"
            },
            "message": "Do u know y **LOVE IS BLIND**\nbcoz..\n''ur mom started to love u before seeing ur face''....!",
            "updated_time": "2010-10-05T13:41:42+0000",
            "comments": {
                "data": [
                    {
                        "id": "136104923104306_1075253",
                        "from": {
                            "name": "Hressence Ec",
                            "id": "1464305271"
                        },
                        "message": "this I would agree..love is surely blind..",
                        "created_time": "2010-10-12T01:40:47+0000",
                    }
                ]
            }
        }

我目前的代码：

$data=json_decode(file_get_contents('https://myurl/where/this/data/is'));
foreach($data as $dts){
echo "$dts->message";
};

我需要提取评论.. 当我尝试

时

foreach($data->comments->data as $dts){
echo "$dts->message";
};

它返回null！请帮忙

Answer 1

您的$data实际上是一个带有 data 属性的对象，该属性是一个包含另一个对象的数组，其中包含您正在寻找的 comments 对象。所以：

foreach ($data->data as $item) {
    foreach ($item->comments->data as $comment) {
        echo $comment->message;
    }
}

Answer 2

我建议你把它转换成一个关联数组：

$data=json_decode(file_get_contents('https://myurl/where/this/data/is'), true);

并查看结构。

我认为你的循环必须如下：

foreach($data['data'] as $dts) {
    echo $dts['message'];
}

更新虽然我能够修复JSON（至少现在似乎很好）json_decode仍然会返回null。没有线索的方式。首先确保您的JSON字符串有效！

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2 个答案: