我想获取表格列中两个字符串之间的字符串。如何选择列?我写过两边的字符串。任何人都可以帮我如何在这里包含字符串的列名吗?
DECLARE @Text NVARCHAR(MAX)
SELECT
SUBSTRING(@Text, CHARINDEX('Manufacturer Name : ', @Text),
CHARINDEX('Manufacturer Part',@text) - CHARINDEX('Manufacturer Name : ', @Text) + LEN('Manufacturer Part'))
FROM
tbIMPACArchiveNew
WHERE
(Description LIKE '%Manufacturer Name: %'
OR Description LIKE '%Manufacturer Name : %')
AND Description LIKE '%Manufacturer Part%'
预期结果:
Column A Expected result
Manufacturer Name : ABC Manufacturer Part Number : XVB-C2B4 ABC
Manufacturer Name : DEF Manufacturer Part Number : 3RH1924-1GP11 DEF
Manufacturer Name : ABJ Manufacturer Part Number : FLDP-IOM248-0001 ABJ
Manufacturer Name : HIJ Manufacturer Part Number : L12/5MLLD0035 HIJ
Manufacturer Name : abhkdk Manufacturer Part Number : PEH1083510 abhkdk
Manufacturer Name : 1245 PUMP Manufacturer Part Number : 02-1010-55 1245
答案 0 :(得分:2)
对于以下的样本数据
declare @table table (id int identity(1,1), data varchar(1000), descr varchar(1000))
insert into @table values ('Manufacturer Name : Manufacturer 1 Manufacturer Part : asjdfj','First Manufacturer')
insert into @table values ('Manufacturer Name : Manufacturer 2 Manufacturer Part : asjsadfasdfdfj','Second Manufacturer')
insert into @table values ('Manufacturer Name : Manufacturer 3 Manufacturer Part : er6ty','Third Manufacturer')
你可以使用
select substring(data,
charindex('Manufacturer Name : ', data) + len('Manufacturer Name : '),
charindex('Manufacturer Part : ',data) - len('Manufacturer Part :') - 2) as Manufacturer_Name
, descr
from @table
如果您注意到我在子字符串末尾删除了2个字符以消除' M'来自Manufacturer Part
和实际文本之前的空格。您可以使用RTRIM
,但我选择了这种方式。
答案 1 :(得分:1)
这是一种在两个固定字符串之间提取文本的方法。不完全确定你使用@Text变量做了什么,所以我在下面用它作为例子。
DECLARE @Text NVARCHAR(MAX) = 'blah blah Manufacturer Name : MY NAME Manufacturer Part blah blah'
SELECT SUBSTRING(@Text, CHARINDEX('Manufacturer Name : ', @Text) + LEN('Manufacturer Name : ') + 1, CHARINDEX('Manufacturer Part',@Text) - (CHARINDEX('Manufacturer Name : ', @Text) + 2 + LEN('Manufacturer Name : ')) )
SELECT SUBSTRING(Description, CHARINDEX('Manufacturer Name : ', Description) + LEN('Manufacturer Name : ') + 1, CHARINDEX('Manufacturer Part',Description) - (CHARINDEX('Manufacturer Name : ', Description) + 2 + LEN('Manufacturer Name : ')) )
FROM tbIMPACArchiveNew
WHERE Description LIKE '%Manufacturer Name : %Manufacturer Part'
答案 2 :(得分:0)
我认为这就是你想要的
SELECT SUBSTRING ( Description , 20 , CHARINDEX("Manufacturer Part") - 20)
FROM tbIMPACArchiveNew;
其中20
是"制造商名称的长度:"
答案 3 :(得分:0)
您可以获得第4个空格的索引并删除前20个。
SELECT SUBSTRING ( Description , 20 , instr(Description,' ',1,4 ) - 20)
FROM tbIMPACArchiveNew;