Question

我有一个来自FIFA的足球运动员的数据库，我可以根据他们的名字从我的Android应用程序中搜索它。我希望能够根据玩家评分来搜索它，但我无法做到这一点。

这就是我尝试从我的应用程序发送我拥有的两个条件（玩家名称和评级）的方式，这是它不起作用的地方。如果我只有Uri.builder()个searchQuery变量，这是播放器的名称，它就可以工作。但是当我尝试使用变量Uri.builder()添加另一个minRating时，它无法建立与数据库的连接。

  // Setup HttpURLConnection class to send and receive data from PHP and MySQL
            conn = (HttpURLConnection) url.openConnection();
            conn.setReadTimeout(READ_TIMEOUT);
            conn.setConnectTimeout(CONNECTION_TIMEOUT);
            conn.setRequestMethod("POST");

            // setDoInput and setDoOutput to true as we send and recieve data
            conn.setDoInput(true);
            conn.setDoOutput(true);

            // add parameter to our above url
            Uri.Builder builder = new Uri.Builder().appendQueryParameter("searchQuery", searchQuery);
            String query = builder.build().getEncodedQuery();

            Uri.Builder builder2 = new Uri.Builder().appendQueryParameter("minRating", minRating);
            String minRating = builder2.build().getEncodedQuery();

            OutputStream os = conn.getOutputStream();
            BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(os, "UTF-8"));
            writer.write(query);
            writer.write(minRating);
            writer.flush();
            writer.close();
            os.close();
            conn.connect();

这是我使用PHP文件接收数据并查询数据库的方式：

<?php
 include 'config.inc.php';

 if(isset($_POST['searchQuery']))
 {
      $search_query=$_POST['searchQuery'];
      $min_rating=$_POST['minRating'];

      $sql = "SELECT Name, Club_Position, Rating from spillere where Name LIKE '%$search_query%'
              AND Rating > $min_rating";

      $statement = $conn->prepare($sql);
  $statement->bindParam(':search_query',$search_query, PDO::PARAM_STR);
      $statement->execute();
      if($statement->rowCount())
      {
    $row_all = $statement->fetchall(PDO::FETCH_ASSOC);
    header('Content-type: application/json');
    echo json_encode($row_all);
      }  
      elseif(!$statement->rowCount())
      {
    echo "no rows";
      }
 }    
 ?>

这就是我的堆栈跟踪：

Image of stacktrace

如何从我的Android应用程序中获取两个或更多搜索条件，将其发送到PHP文件并查询数据库？

Answer 1

 Uri.Builder builder = new Uri.Builder().appendQueryParameter("searchQuery", searchQuery);
 String query = builder.build().getEncodedQuery();

 Uri.Builder builder2 = new Uri.Builder().appendQueryParameter("minRating", minRating);
 String minRating = builder2.build().getEncodedQuery();

在单个查询参数中结合上述两个参数：

Uri.Builder builder = new Uri.Builder()
             .appendQueryParameter("searchQuery", searchQuery)
             .appendQueryParameter("minRating", minRating);
String query = builder.build().getEncodedQuery();

//Now write query param to OutputStream 
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(os, "UTF-8"));
writer.write(query);

Android - 如何使用PHP搜索多个标准的MySQL数据库？

1 个答案: