Question

我有两个数据帧，

new1.
      Name       city
 0    sri won    chn
 1    pechi won  pune
 2    Ram won    mum
 0    pec won    kerala

new3
    req
0   pec
1   mut

我试过了，

mask=new1.Name.str.contains("|".join(new3.req.values.tolist()))
new1[mask]

我到了，

 new1[mask]
      Name       city
 1  pechi won    pune
 0  pec won      kerala

as＆＃34; pechi＆＃34;包含＆＃34; pec＆＃34;，它取了这个值。但是我希望值之间没有＆＃34;包含＆＃34;

我想要的输出是，

 new1[mask]
      Name       city
 0  pec won      kerala

Answer 1

您需要\b表示＆＃34;字边界＆＃34;：

a = r'\b(' + "|".join(new3.req.values.tolist()) + r')\b'
print (a)
\b(pec|mut)\b

mask=new1.Name.str.contains(a)
df = new1[mask]
print (df)
      Name    city
0  pec won  kerala

Answer 2

分隔符中需要空格

In [1350]: new1
Out[1350]:
        Name    city
0    sri won     chn
1  pechi won    pune
2    Ram won     mum
0    pec won  kerala

In [1351]: new3
Out[1351]:
   req
0  pec
1  mut

In [1352]: ' | '.join(new3.req)
Out[1352]: 'pec | mut'

In [1353]: new1.Name.str.contains(' | '.join(new3.req))
Out[1353]:
0    False
1    False
2    False
0     True
Name: Name, dtype: bool

In [1354]: new1[new1.Name.str.contains(' | '.join(new3.req))]
Out[1354]:
      Name    city
0  pec won  kerala

比较两个Dataframe列以检查它们在python中是否具有相同的值

2 个答案: