Question

我需要将以下Unix脚本转换为在Windows上运行。我假设cd命令会更改为调用dir而echo命令更改为调用print。

脚本检查目录中是否有给定文件，如果文件不存在，则脚本循环/休眠，然后再次检查。

我主要是如何最好地转换变量和循环命令，任何提示/提示都会受到赞赏？

cd $DIRECTORY_NAME

echo "You are currently in $(pwd) directory"

numfiles=0

while [ $numfiles -lt "1" ]

do

    export filename=`ls SWIX_BAU_success`
    export numfiles=$(echo $filename | wc -w)
    echo "$numfiles file found"

if [ $numfiles -ge "1" ]

then

    echo "$filename file found"
    exit 0

else

    echo "Incorrect number of files found, 1 file expected"
    numfiles=0
    sleep 300

fi

done

Answer 1

当你撤销这个问题时，我只是在SO上发布这个答案假设SWIX_BAU_success是只有一个文件的（子）目录。

@Echo off

cd /D "%DIRECTORY_NAME%"
echo You are currently in directory: %CD%
Set numfiles=0

For /f "tokens=1,* delims=:" %%A in (
    'Dir /B "SWIX_BAU_success" ^| findstr /n ^ '
) DO Set numfiles=%%a&Set filename=%%B

If %numfiles% equ 1 (
    echo %filename% found
    exit /B 0
) else (
    echo "Incorrect number of files found, 1 file expected"
    set numfiles=0
    Timeout /T 300
)

如何将Unix shell脚本修改为Windows批处理文件？

1 个答案: