Question

我有两个与我合作的模特。第一个是教育模式，其中一个用户可以输入多个教育资格实例：

class Education(models.Model):
    user = models.ForeignKey(User,on_delete=models.CASCADE)
    degree_name = models.CharField(max_length=150,null=True,blank=True)
    institute_name = models.CharField(max_length=150, null=True, blank=True)
    date_start = models.CharField(null=True,blank=True,max_length=25)
    date_end = models.CharField(null=True,blank=True,max_length=25)
    description = models.TextField(null=True,blank=True,max_length=1000)

第二个模型是“用户信息”模型，其中一个用户可以拥有最多一个实例：

class Userinfo(models.Model):
    user = models.ForeignKey(User,on_delete=models.CASCADE)
    user_info = models.ForeignKey(User_info,related_name='user_info',on_delete=models.CASCADE,null=True)

    profile_pic = models.FileField(null=True,blank=True)
    dob = models.CharField(max_length=25,null=True,blank=True)
    nationality = models.CharField(max_length=100, null=True, blank=True)
    headline = models.CharField(max_length=160, null=True,blank=True)
    summary = models.TextField(max_length=1000, null=True, blank=True)
    current_salary = models.FloatField(null=True,blank=True)
    japanese_level = models.CharField(max_length=50, null=True, blank=True)
    english_level = models.CharField(max_length=50, null=True, blank=True)
    career_level = models.CharField(max_length=50,null=True,blank=True)
    availability = models.CharField(max_length=50, null=True, blank=True)
    expected_salary = models.FloatField(null=True, blank=True)
    job_role = models.CharField(max_length=50,null=True)

当我使用任何查询获取“用户信息”的任何实例时：

Userinfo.objects.filter(user=request.user)

我如何关联这两个模型，以便在循环访问Userinfo时，我应该能够在Education模型中获得它的多个实例。我该如何更改模型并查询它们？

Answer 1

我发现您已经拥有Education模型中用户模型的外键。 UserInfo模型中不需要外键。您只需拨打一个额外的电话即可获取给定用户的所有Education个实例：

Education.objects.filter(user=request.user)

或者您可以将request.user更改为您需要获得的实际用户。

修改

不对代码进行任何更改，您可以通过以下方式获取多个实例：

示例views.py

def myView(request): user_info = Userinfo.objects.get(user=request.user) #using get since only 1 instance always educations = Education.objects.filter(user=request.user) #fetching all the instances for the education context_dict = {"user_info": user_info} educations_list = [] for e in educations: educations_list.append(e) # do whatever you need with the educations # you can access user_info fields just by `user_info.field_name` # and you can access the current education fields by `e.field_name` context_dict["educations"] = educations_list return render(request, "template.html", context_dict)

template.html中的示例用法

{% if user_info %} <p>{{ user_info.field_name }}</p> {% if educations %} {% for e in educations %} <div>{{ e.field_name }}</div> {% endfor %} {% endif %} {% endif %}

编辑2（包括多个userinfo实例）

views.py

def myView(request): user_infos = Userinfo.objects.filter() # fetch all instances context_dict = {} result = [] for u in user_infos: temp = [] educations_list = [] educations = Education.objects.filter(user=u.user) # fetch educations for the currently iterated user from user_infos for e in educations: educations_list.append(e) temp.append(u) # append the current user_info temp.append(educations_list) # append the corresponding educations result.append(temp) context_dict["result"] = result return render(request, "template.html", context)

template.html

{% if result %} {% for r in result %} <div>{{ r.0 }}</div>  {% if r.1 %} {% for e in r.1 %} <div>e.degree_name</div>  {% endfor %} {% endif %} {% endfor %} {% endif %}

views.py中的代码并不完美，可能值得重构（如何构建最终的字典），但我相信这会让你知道如何去做。

希望这有帮助！

Answer 2

UITabBarController

此查询将为ui = Userinfo.objects.filter(user=request.user)提供Userinfo的所有实例。你可以像这样循环访问request.user属性的值：

Education

Answer 3

我想也许您的UserInfo模型可以与用户建立OneToOne关系，然后执行类似

的操作

UserInfo.objects.filter(user=request.user).education_set.all()

希望这有帮助。

祝你好运！

django：当Userinfo的每个实例在Education模型中有多个实例时，如何获得模型Userinfo的多个实例

3 个答案: