我有这个对象:
{"Header":["Date","Test1","Test2","Test3","N/A","Test4","Test5"],
"Values":[["Total Unique","79 280","1 598","5 972","20","2 633","9 696"],
["2017-06-19","28 026","1 036","3 667","20","1 097","4 672"]]}
我想要的结果是:
Date
2017-06-19
我能够实现的目标:
Date ["2017-06-19","28 026","1 036","3 667","20","1 097","4 672"]
使用此代码:
vm.header = data.Header[0];
vm.data1 = data.Values[1];
答案 0 :(得分:1)
因为data.Values是一个二维数组,您可以通过将代码更改为:
来获得所需的结果vm.header = data.Header[0];
vm.data1 = data.Values[1][0];
答案 1 :(得分:1)
Header[0] = 'Date';
Header[1]= 'Test1';
Header[2]= 'Test2';
Header[3]= 'Test3';
Header[4]= 'N/A';
Header[5]= 'Test4';
Header[6]= 'Test5';
Values is 2D array
Values[0] = ["Total Unique","79 280","1 598","5 972","20","2 633","9 696"]
Values[1]=["2017-06-19","28 026","1 036","3 667","20","1 097","4 672"]
到目前为止您所尝试的是data.Header[0]
会给您“约会”。 data.Values[1]
会给你整个数组。所以你需要得到" 2017-06-19"你必须获得该数组的第一个元素,即data.Values[1][0]