我有一个如下的数据框 -
time machine message
6 2017-08-07 05:24:31,955 solid qa : 6502444
20 2017-08-07 05:24:32,024 solid prod : 6502445
32 2017-08-07 05:24:32,033 solid qa : 6502445
44 2017-08-07 05:24:32,041 solid prod : 6502446
56 2017-08-07 05:24:32,055 solid qa : 6502446
68 2017-08-07 05:24:32,063 solid prod : 6502447
80 2017-08-07 05:24:32,071 solid qa : 6502450
92 2017-08-07 05:24:32,079 solid prod : 6502451
92 2017-08-07 05:24:32,079 solid qa : 6502452
104 2017-08-07 05:24:32,086 solid prod : 6502453
116 2017-08-07 05:24:32,094 liquid qa : 700001
128 2017-08-07 05:24:32,101 liquid prod : 700004
140 2017-08-07 05:24:32,108 liquid qa : 700002
152 2017-08-07 05:24:32,115 liquid prod : 700005
164 2017-08-07 05:24:32,126 liquid qa : 700007
176 2017-08-07 05:24:32,133 liquid prod : 700010
188 2017-08-07 05:24:32,140 liquid qa : 700008
200 2017-08-07 05:24:32,147 liquid prod : 700011
我想知道特定qa和prod的消息字段中缺少哪些数字。如果缺少任何数字,那么我想要丢失多少个号码,以前的可用开始时间和下一个可用的结束时间以及相应的消息号。
我想以csv格式生成一个输出文件,其中包含如下所示的标题 -
machine,message_header,missing_number_size,start,end,start_time,end_time
Output.csv 将如下所示 -
machine,message_info,missin_number_size,start,end,start_time,end_time
solid,qa,3,6502446,6502450,2017-08-07 05:24:32,055,2017-08-07 05:24:32,071
solid,qa,1,6502450,6502452,2017-08-07 05:24:32,071,2017-08-07 05:24:32,079
solid,prod,3,6502447,6502451,2017-08-07 05:24:32,063,2017-08-07 05:24:32,079
solid,prod,1,6502451,6502453,2017-08-07 05:24:32,079,2017-08-07 05:24:32,086
liquid,qa,4,700002,700007,2017-08-07 05:24:32,108,2017-08-07 05:24:32,126
liquid,prod,4,700005,700010,2017-08-07 05:24:32,115,2017-08-07 05:24:32,133
如何检查消息列的顺序并生成上面的csv文件?