销售数据库中有3个表:orders(order_id, user_id, item_id, quantity, date), users(user_id, name, discount_percent) and items(item_id, name, type, price)
。我正在尝试按用户分组的每月利润生成一份报告,该日期必须看起来像这样(摘录):
|-------user--------|----------day_1--------|---------day_2---------|---------day_3---------| etc. |
|-user_name_1-|-sum_of_expenses-|-sum_of_expenses-|-sum_of_expenses-| etc. |
|-user_name_2-|-sum_of_expenses-|-sum_of_expenses-|-sum_of_expenses-| etc. |
我使用以下准备好的声明来实现这一目标:
SELECT
GROUP_CONCAT(DISTINCT CONCAT('SUM(IF(DATE(orders.date) = \'',
DATE(orders.date),
'\', orders.quantity * items.price * (1 - users.discount_percent / 100), 0)) AS ',
DATE(orders.date))
ORDER BY DATE(orders.date))
INTO @sql FROM
orders;
SET @sql = CONCAT('SELECT users.name, ', @sql, ' FROM
users
INNER JOIN
orders ON users.user_id = orders.user_id
INNER JOIN
items ON orders.item_id = items.item_id
GROUP BY users.name
ORDER BY users.user_id');
PREPARE statement FROM @sql;
EXECUTE statement;
DEALLOCATE PREPARE statement;
出于某种原因,它给了我一个警告:
1 row(s) affected, 1 warning(s): 1260 Row 8 was cut by GROUP_CONCAT()
然后是错误:
Error Code: 1064. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '2015-01-01,SUM(IF(DATE(orders.date) = '2015-01-02', orders.quantity * items.pric' at line 1
我认为这与日期或引号的格式有关,但我输入的所有内容都无法修复。
此外,我正试图弄清楚如何通过php的mysqli prepare()方法实现这个复杂的语句。
答案 0 :(得分:2)
对于第一个警告,MySql group_concat函数默认限制为1024。
您可以使用以下方法增加查询前的限制:
SET @@group_concat_max_len = 32000;
答案 1 :(得分:0)
每当SQL中出现语法错误时,通过查看生成的最终SQL,不用于生成SQL的代码,更容易找到问题。
在这种情况下,我认为您会发现您定义的列别名缺少引号:
SUM(IF(DATE(orders.date) = '2015-01-01',
orders.quantity * items.price * (1 - users.discount_percent / 100),
0)
) AS 2015-01-01
这不是合法的列别名。你必须在它周围加上引号。
我建议您在创建准备好的SQL语句时使用QUOTE()函数:
SELECT
GROUP_CONCAT(DISTINCT CONCAT('SUM(IF(DATE(orders.date) = ',
QUOTE(DATE(orders.date)),
', orders.quantity * items.price * (1 - users.discount_percent / 100), 0)) AS ',
QUOTE(DATE(orders.date)))
ORDER BY DATE(orders.date))
INTO @sql FROM
orders;