我正在编写一个程序来填充一个0字节的USB驱动器,以便将其转换为可引导的磁盘(该部分将在稍后发布)。
现在我拥有的是:
import io
import lib
class CancelBlockCipherException(Exception): pass
class Formatter(object):
def __init__(self, usb):
self.usb = usb
def _erase_all(self, block_cipher):
with io.FileIO(self.usb, "w") as _usb:
while _usb.write(block_cipher): pass
def format_usb(self, size, default="y"):
block_cipher = b"\0" * size
confirmation = lib.settings.prompt(
"Your USB is about to be completely erased, everything on this "
"drive will be gone, are you sure you want to continue", "y/N(default '{}')".format(default)
)
if confirmation.lower().startswith("y") or confirmation == "":
lib.settings.LOGGER.warning("Erasing USB content..")
self._erase_all(block_cipher)
elif confirmation.lower() == "" or confirmation is None:
lib.settings.LOGGER.warning("Erasing USB content..")
self._erase_all(block_cipher)
else:
raise CancelBlockCipherException("User aborted block cipher.")
这将采取USB的大小(以字节为单位),并将\0
写入/dev/sdb1
,直到它完全填充0字节的USB文件(至少是什么?我认为正在发生,我以前错了。)我想做的是更快地写入文件。现在这可能需要10-15分钟才能完成,因为写\0
1,875,615,744(1.75GB)次可能会占用大量时间。如何使用纯python成功格式化USB,更高效,更快速?
答案 0 :(得分:0)
一种非常混乱的方式是将代码中的一百万份def compute_probability_distribution(sides):
print([(sides+1, sides), (sides, sides-1), (sides+2, sides-1)])
硬编码,然后只需要将其写入磁盘即可。我不确定这是否会大大缩短时间。