我有一个数据库,其中包含一个用于引擎的表(EngineId,Make,Model,SerialNumber等)以及一个在引擎上有Test值的表(TestId,EngineId,Value1,Value2等)。
我想从Engines表中选择所有记录以及最新的测试值(可能有多个测试记录,但我只想要最新的)。这似乎很简单,但出于某种原因,我无法获得SQL语法。
我可以开始使用类似下面的内容,但后来我被卡住了。
SELECT e.*, t.Value1, t.Value2
FROM Engine e
left join Event ev on e.EngineID = ev.EngineID
left join Test t on ev.EventID = t.EventID
WHERE ev.EventType = 'TEST'
我可以接近以下内容,但它只返回包含测试数据的记录。我想在没有测试数据的情况下返回引擎记录:
SELECT e.*, t.Nox, t.CO
FROM Engine e
left join Event ev on e.EngineID = ev.EngineID
left join Test t on ev.EventID = t.EventID
left join EventType et on ev.EventTypeId = et.EventTypeID
WHERE Upper(et.Name) = 'TEST'
AND ev.EventDate= ( SELECT MAX(EventDate)
FROM Event ev2
left join EventType et2 on ev2.EventTypeID = et2.EventTypeID
WHERE ev2.EngineID = e.EngineID AND
Upper(et2.Name) = 'TEST')
我可以接近以下内容,但我仍然需要以某种方式加入Test表:
SELECT DISTINCT e.*, om.maxdate
FROM Engine e
LEFT JOIN (
select ev2.EngineID, max(EventDate) as maxdate
from Event ev2
LEFT JOIN EventType et on ev2.EventTypeID = et.EventTypeID
WHERE Upper(et.Name) = 'TEST'
group by EngineID
) om on e.EngineID = om.EngineID
--LEFT JOIN Test t on om.EventID = t.EventID
如果有帮助,我可以执行存储过程。
你问了一些样本数据,所以这里有。我想返回所有引擎记录以及最新的测试值。
引擎
EngineId Make Model SerialNumber
1 Waukesha 5794 C-62124
2 Waukesha 5800 F-199374
3 NULL NULL B-200305
4 Waukesha 6000 D-999777
5 Waukesha 6100 E-877324
6 Briggs & Stratton LW300 SL-122375
7 Briggs & Stratton LW350 SL-375200
8 Briggs & Stratton GS250 LS-988755
9 Briggs & Stratton 5794 SN12345
测试
TestID EventID EngineID TestDate Description Value1 Value2
1 7 1 03/01/17 12:00 AM Testing 30 50
9 8 1 01/01/17 12:00 AM Testing 20 20
17 11 1 12/01/16 12:00 AM Testing 16 15
答案 0 :(得分:1)
你可以使用
SELECT TOP 1 e. *,t.Value1,t.Value2
要获得最高记录并确保顶部是最新记录,请使用
订购表格 ORDER BY column1, column2, ... ASC|DESC
希望这会有所帮助......
答案 1 :(得分:0)
如果您指的是给定引擎的最新TEST事件(基于EventDate),那么它是:
SELECT e.*, t.Value1, t.Value2
FROM Engine e
LEFT JOIN Event ev
ON e.EngineID = ev.EngineID
AND ev.EventType = 'TEST'
AND ev.EventDate = (SELECT MAX(ev2.EventDate)
FROM Event ev2
WHERE ev2.EngineID = e.EngineID
AND ev2.EventType = 'TEST')
LEFT JOIN Test t
ON ev.EventID = t.EventID
请注意,如果最新活动有更多测试记录,则会返回所有测试记录,因为所有测试记录都共享相同的最新EventDate。但这似乎是正确的,因为你没有区分分配给同一事件的多个测试记录,所以它们是相同的。
答案 2 :(得分:0)
当您说您想要最新的测试值时,这意味着您可以通过某种方式识别最新的测试值。这可以通过检索最新的eventdate来完成。
您必须在查询中使用子查询。
SELECT e.*, t.Value1, t.Value2
FROM Engine e
left join Event ev on e.EngineID = ev.EngineID
left join Test t on ev.EventID = t.EventID
WHERE ev.EventType = 'TEST'
AND ev.EventDate= ( SELECT MAX(EventDate)
FROM Event
WHERE Event.EventID = t.EventId
AND Event.EngineID = ev.EngineId )
这应该为您提供引擎上事件的最新测试结果
答案 3 :(得分:0)
您可以使用;with Tcte as (
SELECT e.*
, t.Value1
, t.Value2
, rank() over (partition by e.EngineID order by t.TestDate desc) r
FROM Engine e
left join Event ev on e.EngineID = ev.EngineID
left join Test t on ev.EventID = t.EventID WHERE ev.EventType = 'TEST')
SELECT * FROM Tcte WHERE r=1
函数仅获取每个引擎的最后一次测试。
gcloud --project=$PROJECT compute instances create $VM --zone=$ZONE --machine-type=$MACHINE --scopes=cloud-platform
答案 4 :(得分:0)
试试这个
;with testValues as
( select ev.EngineID, ev.EventId ,t.TestId,t.Value1, t.Value2
,row_number() over(partition by ev.EventId order by ev.EventDate desc)rowNumber
from Event ev
left join Test t on ev.EventID = t.EventID
WHERE ev.EventType = 'TEST'
)
SELECT e.*, v.Value1, v.Value2
FROM Engine e
left join testValues v on e.EngineID = v.EngineID and v.rowNumber=1
或者这个
;with testData as
(
SELECT e.*, t.Value1, t.Value2
,row_number() over(partition by ev.EventId order by ev.EventDate desc)rowNumber
FROM Engine e
left join Event ev on e.EngineID = ev.EngineID and ev.EventType = 'TEST'
left join Test t on ev.EventID = t.EventID
)
select * from testData where rowNumber=1