我正在努力更好地理解Dijkstra的算法。我附上了教科书中的算法图像。伪代码显示输入是无向图,但对于有向图,算法是否有任何不同?我已经使用有向图的输入查找算法,但我没有发现任何差异。
Algorithm ShortestPath(G, v)
Input: A simple undirected weighted graph G with nonnegative edge weights and a distinguished vertex v of G
Output: A label D[u], for each vertex u of G, such that D[u] is the length of a shortest path from v to u in G
Initialize D[v]<--0 and D[u]<--+infinity for each vertex u != v.
Let priority queue Q contain all the vertices of G using the D labels as keys.
while Q is not empty do
{pull a new vertex u into the cloud}
u<-- Q.removeMin()
for each vertex z adjacent to u such that z is in Q do
{preform the relaxation procedure on edge (u,z)}
if D[u]+w((u,z))<D[z] then
D[z]<-- D[u]+w((u,z))
change to D[z] the of vertex z in Q
return the label D[u] of each vertex u
答案 0 :(得分:1)
您可以在有向图和无向图中使用Dijkstra算法,因为当您有从边缘列表前往的边时,只需将边添加到PriorityQueue中。例如,如果我的一个节点具有从A到B的权重为3的边缘,那么如果它从BI指示,则无法将边缘添加回A,而从AI可以添加它到B.
与其他答案一样,请确保不要将其与重量混淆。 Dijkstra的算法在正加权图上运行,否则优先级队列将无用。