Question

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，则只希望它打印所选的课程

eqid == allowed_classes

我试过了

allowed_classes = set(["N001", "N002", "N003", "N004", "E001", "E002", "E003"])  # etc
default_class = "N004" #If no class is specified it is defaulted to N004

eqid = raw_input('Please swipe your card: ').strip().upper()
class_ = eqid if eqid in allowed_classes else default_class
print("Selected class", class_)

但这不起作用，甚至不会运行。

完整代码：

eqid = raw_input('Please swipe your card: ').strip().upper()
if eqid in allowed_classes 
    class_ = eqid
    print('Selected class: ', class_)
else default_class

（格式正确无法在此处格式化抱歉：/）

Answer 1

简单的答案是你做不到。您将ternary operator与if statement混淆，可能是因为它们有一些语法相似性。三元运算符根据条件返回两个表达式之一：

expr1 if condition else expr2

这是表达式，而不是语句块。您无法在表达式中添加continue。

相反，你必须使用完整的表格：

if eqid in allowed_classes:
    class_ = eqid
    print('Selected class: ', class_)
    continue
else:
    class_ = default_class

这就是你需要的吗？

如何将继续添加到if块

1 个答案: