我已经创建了一个带有python函数的部署包,用于创建一个使用AWS Lambda的google驱动器文件夹。然后我尝试测试它,我得到一个错误:
{
"errorMessage": "main() takes from 0 to 1 positional arguments but 2 were given",
"errorType": "TypeError",
"stackTrace": [
[
"/var/runtime/awslambda/bootstrap.py",
249,
"handle_event_request",
"result = request_handler(json_input, context)"
]
]
}
我的.zip中有2个主要文件。第一个文件包含main函数,另一个文件包含安全凭证,另一个文件夹和文件是lib。名为lambda_function.py的主文件,代码为:
from __future__ import print_function
import httplib2
import os
from apiclient import discovery
from oauth2client import client
from oauth2client import tools
from oauth2client.file import Storage
try:
import argparse
flags=argparse.ArgumentParser(parents=[tools.argparser]).parse_args()
except ImportError:
flags=None
# If modifying these scopes, delete your previously saved credentials
# at ~/.credentials/drive-python-quickstart.json
SCOPES='https://www.googleapis.com/auth/drive.file'
CLIENT_SECRET_FILE='client_secret.json'
APPLICATION_NAME='Drive API Python Quickstart'
def get_credentials():
"""Gets valid user credentials from storage.
If nothing has been stored, or if the stored credentials are invalid,
the OAuth2 flow is completed to obtain the new credentials.
Returns:
Credentials, the obtained credential.
"""
home_dir=os.path.expanduser('~')
credential_dir=os.path.join(home_dir, '.credentials')
if not os.path.exists(credential_dir):
os.makedirs(credential_dir)
credential_path=os.path.join(credential_dir,
'drive-python-quickstart.json')
store=Storage(credential_path)
credentials=store.get()
if not credentials or credentials.invalid:
flow=client.flow_from_clientsecrets(CLIENT_SECRET_FILE, SCOPES)
flow.user_agent=APPLICATION_NAME
if flags:
credentials=tools.run_flow(flow, store, flags)
print('Storing credentials to ' + credential_path)
return credentials
def main(drive_service=None):
"""Shows basic usage of the Google Drive API.
Creates a Google Drive API service object and outputs the names and IDs
for up to 10 files.
"""
credentials=get_credentials()
http=credentials.authorize(httplib2.Http())
service=discovery.build('drive', 'v3', http=http)
file_metadata={
'name': 'Invoices',
'mimeType': 'application/vnd.google-apps.folder'
}
file=service.files().create(body=file_metadata,
fields='id').execute()
print('Folder ID: %s' % file.get('id'))
if __name__ == '__main__':
main()
并且我在AWS Lambda中的处理程序是lambda_function.main,如果我尝试测试我会收到错误。如果我在控制台上执行此操作,则会成功执行此代码并在google drive api中创建一个文件夹。也许谁知道我做错了什么?请帮助。
答案 0 :(得分:0)
AWS Lambda处理程序有两个参数event和context,例如:
def lambda_handler(event, context):