如何迭代Python中的字节对象?

时间:2017-08-01 21:22:34

标签: python django python-3.x

我正在Django中做一个POST请求,我收到一个字节对象。我需要计算特定用户在此对象上显示的次数,但我收到以下错误TypeError: 'int' object is not subscriptable。这就是我到目前为止所做的:

def filter_url(user):
    ''' do the POST request, this code works '''

    filters = {"filter": {
    "filters": [{
        "field": "Issue_Status",
        "operator": "neq",
        "value": "Queued"
    }],
    "logic": "and"}}

    url = "http://10.61.202.98:8081/Dev/api/rows/cat/tickets?"
    response = requests.post(url, json=filters)
    return response

def request_count():
    '''This code requests a POST method and then it stores the result of all the data 
    for user001 as a bytes object in the response variable. Afterwards, a call to the 
    perform_count function is made to count the number of times that user user001 appeared.'''

    user = "user001"
    response = filter_url(user).text.encode('utf-8')
    weeks_of_data = []     
    weeks_of_data.append(perform_count(response))

def perform_count(response):
    ''' This code does not work, int object is not subscriptable '''
    return Counter([k['user_id'] for k in response)

#structure of the bytes object
b'[{"id":1018002,"user_id":"user001","registered_first_time":"Yes", ...}]'

# This is the result that indicates that response is a bytes object.
print(type(response))
<class 'bytes'>

如何使用peform_count()函数计算user001出现的次数?该功能需要哪些修改才能工作?

1 个答案:

答案 0 :(得分:1)

你确实收到字节,是的,然后让requests库对其进行解码(通过response.text属性,automatically decodes the data)然后重新编码你自己:

response = filter_url(user).text.encode('utf-8')

除了使用response.content attribute代替以避免解码 - &gt;编码往返,你应该只是decode the data as JSON

data = filter_url(user).json()

现在data是一个词典列表,您的perform_count()函数可以直接对其进行操作。