我想用a生成这个案例 $ scope.type [i](来自数据库的json数组),怎么做?
$data = array('api'=>'123344');
curl_setopt_array($curl, array(
CURLOPT_URL => "http://example.com/api",
CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
CURLOPT_CUSTOMREQUEST => "POST",
CURLOPT_POSTFIELDS => $data,
CURLOPT_HTTPHEADER => array(
"cache-control: no-cache",
"content-type: multipart/form-data; boundary=----WebKitFormBoundary7MA4YWxkTrZu0gW"
),
));
答案 0 :(得分:0)
您必须将正确的对象值传递给与您的案例匹配的开关。在下面的示例中,如果您从输入传递电话或鞋子,则会触发开关。
var myApp = angular.module('myApp', []);
myApp.controller('ctrl', ['$scope', function ($scope) {
$scope.type = [{nomcarac: "phone"}, {nomcarac: "shoes"}];
$scope.getValuesList = function(index) {
switch ($scope.type[index].nomcarac){
case $scope.type[index].nomcarac:
$scope.valuelist = $scope.type[index].nomcarac +" " + "worked";
console.log($scope.valuelist);
break;
default:
$scope.valuelist = "Nothing worked";
break;
}
};
for(var i=0;i<$scope.type.length;i++)
$scope.getValuesList(i);
}]);
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="myApp" ng-controller="ctrl">
</div>
答案 1 :(得分:0)
$scope
变量就像普通的javascript变量一样,您可以使用如下变量访问子级别:
item.valuelist = angular.copy($scope[item.type + 'list']);
如果您担心字符串不正确,可以稍后检查null。
答案 2 :(得分:0)
我希望它能按照您的期望:
运作
var myApp = angular.module('myApp',[]);
myApp.controller('MyCtrl', function($scope) {
$scope.type = [{nomcarac: "phone"}, {nomcarac: "shoes"}];
$scope.getValuesList = function(item) {
switch (item.nomcarac) {
case item.nomcarac:
item.valuelist = angular.copy($scope.phonelist);
break;
default:
item.valuelist = [];
break;
}
};
for (var i in $scope.type) {
$scope.getValuesList($scope.type[i]);
}
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-controller="MyCtrl" ng-app="myApp">
</div>
&#13;