Question

首先我创建了一个esprima AST，然后我想使用estraverse删除一个节点，最后用escodegen重新生成代码。但是我得到了一个错误。

我尝试的代码是：

var esprima = require('esprima');
var estraverse = require('estraverse');
var escodegen = require('escodegen');

(function () {
//build an ast with 2 lines of code
var ast = esprima.parse("console.log('1');\n console.log('2');")
console.log("original code:\n" + escodegen.generate(ast));
console.log();

//change one of the lines, works
ast = estraverse.replace(ast, {
  enter: function (node) {
  },
  leave: function (node) {
    if (node.type === esprima.Syntax.CallExpression) {
      this.break();
      return esprima.parse("console.log('patch');").body[0].expression;
    }
  }
});
console.log("patched code:\n" + escodegen.generate(ast));
console.log();

//remove one of the lines, error
ast = estraverse.replace(ast, {
  enter: function (node) {
  },
  leave: function (node) {
    if (node.type === esprima.Syntax.CallExpression) {
      this.break();
      return this.remove();
    }
  }
});
console.log("removed node:\n" + escodegen.generate(ast));
})()

错误跟踪是：

C:\temp\node_modules\escodegen\escodegen.js:2450
        type = expr.type || Syntax.Property;
                  ^

TypeError: Cannot read property 'type' of null
    at CodeGenerator.generateExpression (C:\temp\node_modules\escodegen\escodegen.js:2450:20)
    at CodeGenerator.ExpressionStatement (C:\temp\node_modules\escodegen\escodegen.js:1335:28)
    at CodeGenerator.generateStatement (C:\temp\node_modules\escodegen\escodegen.js:2469:33)
    at CodeGenerator.Program (C:\temp\node_modules\escodegen\escodegen.js:1717:43)
    at CodeGenerator.generateStatement (C:\temp\node_modules\escodegen\escodegen.js:2469:33)
    at generateInternal (C:\temp\node_modules\escodegen\escodegen.js:2490:28)
    at Object.generate (C:\temp\node_modules\escodegen\escodegen.js:2558:18)
    at C:\temp\bug1.js:35:45
    at Object.<anonymous> (C:\temp\bug1.js:38:3)
    at Module._compile (module.js:570:32)

我做错了吗？这是escodegen中的错误还是estraverse中的错误？

提前致谢。

Answer 1

我在github上放了一个issue，我得到了一个答案，我做了一个无效的AST。

删除CallExpression会将其父ExpressionStatement留空，因此无效。解决方案就是删除ExpressionStatement。

此代码按预期工作：

var esprima = require('esprima');
var estraverse = require('estraverse');
var escodegen = require('escodegen');

(function () {
  //build an ast with 2 lines of code
  var ast = esprima.parse("console.log('1');\n console.log('2');")
  console.log("original code:\n" + escodegen.generate(ast));
  console.log();

  //remove one of the lines, works!
  var done = false;
  ast = estraverse.replace(ast, {
    enter: function (node) {
      if (done)
        return this.break();
      if (node.type === esprima.Syntax.ExpressionStatement) {
        done = true;
        this.remove();
      }
    },
    leave: function (node) {
      if (done)
        return this.break();
    }
  });
  console.log("removed node:\n" + escodegen.generate(ast));
})()

输出：

original code:
console.log('1');
console.log('2');

removed node:
console.log('2');

删除节点后使用escodegen生成代码时出错

1 个答案: