Question

我正在尝试使用命令ZipDirectoryContents创建一个包含Delphi Tokyo的zip文件，该命令有4个参数。他们是

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是否有人可以告诉我如何使用这些参数，特别是TZipProgressEvent来显示zip文件的进度，因为它正在添加目录中的文件。感谢

Answer 1

以下是Embarcadero提供的答案

unit Unit16;

interface

uses
Winapi.Windows, Winapi.Messages, System.SysUtils, System.Variants, System.Classes, Vcl.Graphics,
  Vcl.Controls, Vcl.Forms, Vcl.Dialogs, Vcl.StdCtrls,System.Zip, Vcl.ComCtrls;

type
  TForm16 = class(TForm)
    Button1: TButton;
    ProgressBar1: TProgressBar;
    StaticText1: TStaticText;
    procedure Button1Click(Sender: TObject);
  private
    { Private declarations }
    PreviousFilename : string;
  public
    { Public declarations }

    procedure OnZipProgressEvent (Sender: TObject; FileName: string; Header: TZipHeader; Position: Int64);
  end;

var
  Form16: TForm16;

implementation

{$R *.dfm}


procedure TForm16.Button1Click(Sender: TObject);
begin
    TZipFile.ZipDirectoryContents('C:\temp\Test.zip','c:\temp\zipTest',zcDeflate,OnZipProgressEvent);
end;

procedure TForm16.OnZipProgressEvent(Sender: TObject; FileName: string;
  Header: TZipHeader; Position: Int64);
begin
  if PreviousFilename <> FileName then
  begin
    StaticText1.Caption := ExtractFileName(FileName);
    PreviousFilename := FileName;
    ProgressBar1.Position := 0;
  end
  else
    ProgressBar1.Position := (Position * 100) div Header.UncompressedSize ;
  Application.ProcessMessages;
end;

end.

使用Delphi Toyko在进程示例中创建Zip文件

1 个答案: