Question

根据git help clone的输出，--local选项执行以下操作：

   --local, -l
       When the repository to clone from is on a local machine, this flag bypasses the normal "Git
       aware" transport mechanism and clones the repository by making a copy of HEAD and everything
       under objects and refs directories. The files under .git/objects/ directory are hardlinked to
       save space when possible.

       If the repository is specified as a local path (e.g., /path/to/repo), this is the default, and
       --local is essentially a no-op. If the repository is specified as a URL, then this flag is
       ignored (and we never use the local optimizations). Specifying --no-local will override the
       default when /path/to/repo is given, using the regular Git transport instead.

如果我正确读取此内容，则第二段说明只要给出本地路径，此选项将默认为on，并且只要给定路径不是本地路径，就会忽略该选项。那么重点是什么？它怎么能产生任何影响呢？它是否基本上是一个无操作的存根，以便在它执行某些操作时与旧版本的git兼容？

Answer 1

这是泄露的技术细节 - 实现--no-X选项的方法。不是单独定义--no-local，而是选项--local，它是noop，但它有--no-*版本。同样的方式（虽然在帮助中没有提到）你可以运行git clone --checkout ...但它不会影响任何东西，因为克隆默认检出。

PS：some long time ago it was not a default，所以使用它确实有意义。

当与git clone [path]一起使用时， - local实际上做了什么吗？

1 个答案: