Question

说我有一个数字列表：

foo = [random.randint(0, 9) for n in range(10)]

我有一个功能

def bar(lst):
    total = 0
    for i in lst:
        total += i
        if total % 4 == 0:
            print "passed multiple of 4"

bar(foo)

如果total跳过4的倍数，如何让print语句执行？

编辑：说foo = [4,5]，然后total获取值0，4和9。我希望print语句执行两次，一次用于4，一次用于8，其中total＆＃34;跳过＆＃34;当它从4跳到9时。

Answer 1

我希望print语句执行两次，一次执行4次，执行一次，一次执行8次，总共＆＃34;跳过＆＃34;当它从4跳到9时。

所以基本上，你不想检查模数，而只是检查总数是否超过4的倍数。

这样的事情：

def bar(lst):
    total = 0
    # keep track of the numbers we need to “pass” to print the notice; the first one is 4
    passed = 4

    for i in lst:
        total += i

        # when the total passed the number
        while total >= passed:
            # print the notice
            print('passed multiple of 4, total is {0}'.format(total))
            # and skip to the next number
            passed += 4

>>> bar([4, 5])
passed multiple of 4, total is 4
passed multiple of 4, total is 9
>>> bar([1, 3, 4])
passed multiple of 4, total is 4
passed multiple of 4, total is 8
>>> bar([1, 12])
passed multiple of 4, total is 13
passed multiple of 4, total is 13
passed multiple of 4, total is 13

如何判断数字何时传递了另一个数字的倍数？

1 个答案: