我试图将函数库转换为使用JSDocs，而我在将多行注释块的第一个实例转换为单行时出现问题@description
在示例中，我试图创建一个正则表达式，将第3行和第4行转换为以下行，而不修改其他注释块。
///@description Returns a string formatted according to the given format string using the given date-time value or current local time if no date-time is given.
我已经玩了一段时间并且已经能够选择第一段代码但是还没有能够让新线路只能选择第一次出现。
示例功能
date_format
// Returns a string formatted according to the given format string using
// the given date-time value or current local time if no date-time is given.
// format string controlling date formatting, string
// datetime date-time value, real (optional)
// Day format characters:
// d - day of the month with leading zeros, 2 digits with leading zeros; 01 through 31
// D - day of the week, textual, 3 letters; Fri
// j - day of the month without leading zeros; 1 through 31
// l - day of the week, textual, long; Friday
// N - ISO 8601 day number of the week; 1 (Monday) through 7 (Sunday)
// S - English ordinal suffix, textual, 2 characters; st, nd, rd, th
// w - day of the week, numeric, 0 (Sunday) through 6 (Saturday)
// z - day of the year (starting from zero); 0 through 365
// Week format characters:
// W - ISO 8601 week number of year, weeks starting on Monday; 42
// Month format characters:
// F - month, textual, long; January
// m - month with leading zeros; 01 through 12
// M - month, textual, 3 letters; Jan
// n - month without leading zeros; 1 through 12
// t - number of days in the given month; 28 through 31
// Year format characters:
// L - whether it is a leap year; 0 or 1
// o - ISO 8601 year, like Y unless ISO week belongs to prev or next year; 2008
// Y - year, 4 digits; 1999
// y - year, 2 digits; 99
// Time format characters:
// a - lowercase Ante meridiem and Post meridiem; am or pm
// A - uppercase Ante meridiem and Post meridiem; AM or PM
// g - hour, 12-hour format without leading zeros; 1 through 12
// G - hour, 24-hour format without leading zeros; 0 through 23
// h - hour, 12-hour format; 01 through 12
// H - hour, 24-hour format; 00 through 23
// i - minutes, with leading zero; 00 through 59
// s - seconds, with leading zero; 00 through 59
// Full Date/Time format characters:
// c - ISO 8601 extended format date; 2004-02-12T15:19:21
// r - RFC 2822 formatted data; Thu, 21 Dec 2000 16:01:07 -0000
// U - seconds since the Unix epoch
//
// \ - following character should be returned literally, not interpreted
// Examples:
// date_format("l jS of F Y h:i:s A") == "Sunday 4th of May 2008 05:45:34 PM"
// date_format('\I\t \i\s \t\h\e zS \d\a\y.') == "It is the 124th day."
/// GMLscripts.com/license
{
var str,dat,out,day,month,year,week,weekday,second,minute,hour24,hour12,i,c;
str = argument[0];
if (argument_count > 1) dat = argument[1];
else dat = date_current_datetime();
out = "";
day = date_get_day(dat);
month = date_get_month(dat);
year = date_get_year(dat);
week = date_get_week(dat);
weekday = date_get_weekday(dat);
second = date_get_second(dat);
minute = date_get_minute(dat);
hour24 = date_get_hour(dat);
hour12 = ((hour24+23) mod 12)+1;
for (i=1; i<=string_length(str); i+=1) {
c = string_char_at(str,i);
switch (c) {
case "F":
switch (month) {
case 1: out += "January"; break;
case 2: out += "February"; break;
case 3: out += "March"; break;
case 4: out += "April"; break;
case 5: out += "May"; break;
case 6: out += "June"; break;
case 7: out += "July"; break;
case 8: out += "August"; break;
case 9: out += "September"; break;
case 10: out += "October"; break;
case 11: out += "November"; break;
case 12: out += "December"; break;
}
break;
case "M":
switch (month) {
case 1: out += "Jan"; break;
case 2: out += "Feb"; break;
case 3: out += "Mar"; break;
case 4: out += "Apr"; break;
case 5: out += "May"; break;
case 6: out += "Jun"; break;
case 7: out += "Jul"; break;
case 8: out += "Aug"; break;
case 9: out += "Sep"; break;
case 10: out += "Oct"; break;
case 11: out += "Nov"; break;
case 12: out += "Dec"; break;
}
break;
case "l":
switch (weekday) {
case 0: out += "Sunday"; break;
case 1: out += "Monday"; break;
case 2: out += "Tuesday"; break;
case 3: out += "Wednesday"; break;
case 4: out += "Thursday"; break;
case 5: out += "Friday"; break;
case 6: out += "Saturday"; break;
}
break;
case "D":
switch (weekday) {
case 0: out += "Sun"; break;
case 1: out += "Mon"; break;
case 2: out += "Tue"; break;
case 3: out += "Wed"; break;
case 4: out += "Thu"; break;
case 5: out += "Fri"; break;
case 6: out += "Sat"; break;
}
break;
case "S":
if (day >= 10 && day <= 20) out += "th";
else if ((day mod 10) == 1) out += "st";
else if ((day mod 10) == 2) out += "nd";
else if ((day mod 10) == 3) out += "rd";
else out += "th";
break;
case "o":
if (month == 1 && day <= 3 && week != 1) { out += string(year-1); break; }
if (month == 12 && day >= 29 && week == 1) { out += string(year+1); break; }
case "Y": out += string(year); break;
case "y": out += string_copy(string(year),3,2); break;
case "m": if (month < 10) out += "0";
case "n": out += string(month); break;
case "d": if (day < 10) out += "0";
case "j": out += string(day); break;
case "H": if (hour24 < 10) out += "0";
case "G": out += string(hour24); break;
case "h": if (hour12 < 10) out += "0";
case "g": out += string(hour12); break;
case "i": if (minute < 10) out += "0"; out += string(minute); break;
case "s": if (second < 10) out += "0"; out += string(second); break;
case "a": if (hour24 < 12) out += "am" else out += "pm"; break;
case "A": if (hour24 < 12) out += "AM" else out += "PM"; break;
case "U": out += string(round(date_second_span(dat,25569))); break;
case "z": out += string(date_get_day_of_year(dat)-1); break;
case "t": out += string(date_days_in_month(month)); break;
case "L": out += string(date_leap_year(dat)); break;
case "w": out += string(weekday); break;
case "N": out += string(((weekday+6) mod 7)+1); break;
case "W": out += string(week); break;
case "c": out += date_format("o-m-dTH:i:s",dat); break;
case "r": out += date_format("D, j M Y H:i:s -0000",dat); break;
case "\": i += 1; c = string_char_at(str,i);
default: out += c; break;
}
}
return out;
}
答案 0 :(得分：0)
因此，使用emacs我创建了一个正则表达式搜索并替换：
搜索：
\(^[^/^J]+^J^J\)// +\(.+\)^J// +\(.+\)^J
并替换为：
\1// @description \2 \3^J
请注意，每个^ J都是emacs中的Ctrl-J。
查看IDEA参考资料，我建议您搜索：
(^[^/\n]+\n\n)// +(.+)\n// +(.+)\n
并替换为：
$1// @description $2 $3\n