Question

我正在尝试比较两个单词列表来检查：

word1列表由也在word2列表的同义词中的单词组成
word2 list包含同样位于word1 list

如果单词位于同义词集内，则会返回True

这是我的代码：

from nltk.corpus import wordnet as wn

word1 =  ['study', 'car']
word2 =  ['learn', 'motor']

def getSynonyms(word1):
    synonymList1 = []
    for data1 in word1:
        wordnetSynset1 = wn.synsets(data1)
        tempList1=[]
        for synset1 in wordnetSynset1:
            synLemmas = synset1.lemma_names()
            for i in xrange(len(synLemmas)):
                word = synLemmas[i].replace('_',' ')
                if word not in tempList1:
                    tempList1.append(word)
        synonymList1.append(tempList1)
    return synonymList1


def checkSynonyms(word1, word2):
    for i in xrange(len(word1)):
        for j in xrange(len(word2)):
            d1 = getSynonyms(word1)
            d2 = getSynonyms(word2)
            if word1[i] in d2:
                return True
            elif word2[j] in d1:
                return True
            else:
                return False

print word1
print
print word2
print
print getSynonyms(word1)
print
print getSynonyms(word2)
print 
print checkSynonyms(word1, word2)
print

但这是输出：

['study', 'car']

['learn', 'motor']

[[u'survey', u'study', u'work', u'report', u'written report', u'discipline', 
u'subject', u'subject area', u'subject field', u'field', u'field of study', 
u'bailiwick', u'sketch', u'cogitation', u'analyze', u'analyse', u'examine', 
u'canvass', u'canvas', u'consider', u'learn', u'read', u'take', u'hit the 
books', u'meditate', u'contemplate'], [u'car', u'auto', u'automobile', 
u'machine', u'motorcar', u'railcar', u'railway car', u'railroad car', 
u'gondola', u'elevator car', u'cable car']]

[[u'learn', u'larn', u'acquire', u'hear', u'get word', u'get wind', u'pick 
up', u'find out', u'get a line', u'discover', u'see', u'memorize', 
u'memorise', u'con', u'study', u'read', u'take', u'teach', u'instruct', 
u'determine', u'check', u'ascertain', u'watch'], [u'motor', u'drive', 
u'centrifugal', u'motive']]

False

我们可以看到，word1中的单词'study'也出现在word2＆gt;＆gt;的同义词中。 u'study'

为什么它返回false？

Answer 1

由于您要将word1的字符串值与d2进行比较，请不要使用if word1[i] in d2:，因为它会将word1的字符串值与d2的数组值进行比较，例如它将进行比较：

'study' == [u'survey', u'study', u'work', u'report', u'written report', u'discipline', 
u'subject', u'subject area', u'subject field', u'field', u'field of study', 
u'bailiwick', u'sketch', u'cogitation', u'analyze', u'analyse', u'examine', 
u'canvass', u'canvas', u'consider', u'learn', u'read', u'take', u'hit the 
books', u'meditate', u'contemplate']

绝对会返回False。

因此，不应使用if word1[i] in d2:，而应使用if word1[i] in d2[k]:，其中k是迭代器。

希望它会对你有所帮助。

如何检查单词是否在同义词中？

1 个答案: