Question

我通过jQuery动态生成html字段，工作正常。

这是代码。

jQuery(document).ready(function($) {
    var y = 1;
    jQuery('#add-new-item').on('click',function(e) { 
    jQuery('#item-main-wrap').append('<div class="row"> <h3 class="item_count">Item <span class="item_number">'+ x +'</span> <i class="fa fa-close remove-item" id=""></i></h3> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_name]" type="text" class="form-control" value="" placeholder="Item name / description *" id="" required="required" /> </div> </div> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_size]" type="text" class="form-control" value="" placeholder="Size (if applicable)" id="" /> </div> </div> <div style="clear: both;"></div> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_url]" type="text" class="form-control" value="" placeholder="Item URL *" id="" /> </div> </div> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_colour]" type="text" class="form-control" value="" placeholder="Colour (if applicable)" id="" /> </div> </div> <div style="clear: both;"></div> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_additional_instructions]" type="text" class="form-control" value="" placeholder="Additional instructions (e.g. Please gift wrap, one of each colour) " id="" /> </div> </div> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_quantity]" type="text" class="form-control" value="" placeholder="Quantity *" id="" required="required" /> </div> </div> <div style="clear: both;"></div> </div>');
    y++;
});

问题是，在尝试从PHP中的那些字段中获取值时，它只获取第一个组，即

Array
   (
    [0] => Array
        (
        [item_name] => Neil
        [item_size] => 
        [item_url] => 
        [item_colour] => 
        [item_additional_instructions] => 
        [item_quantity] => 5
    )
)

如果我硬编码html中的所有字段而不是通过jQuery生成它，它可以正常工作并从下面的字段中获取所有值。

Array
(
  [0] => Array
     (
        [item_name] => sadsa
        [item_size] => 
        [item_url] => sada
        [item_colour] => 
        [item_additional_instructions] => 
        [item_quantity] => dsa
     )
  [1] => Array
     (
        [item_name] => sad
        [item_size] => sad
        [item_url] => sad
        [item_colour] => 
        [item_additional_instructions] => 
        [item_quantity] => sadas
     )
  [2] => Array
     (
        [item_name] => sadsad
        [item_size] => 
        [item_url] => asdsad
        [item_colour] => 
        [item_additional_instructions] => dsad
        [item_quantity] => sada
     )
)

对于获取值，我使用以下方法。

if (isset($_POST['submit_request'])) {  
  $personal_shopper_items = $_POST['personal_shopper_item'];
  $count = 2;
  for ( $i = 0; $i < $count; $i++ ) {
    $personal_shopper_items[$i]['item_name'];
  }
  print_r($personal_shopper_items);
}

如果你们想看到这个问题的实时版本，这里是： Live Version
我用过＆＃34; print_r（）＆＃34;用于调试目的。

请在这方面指导我。

提前致谢。

Answer 1

而不是在包含数组的大数组上，你可以做更小的数组并匹配索引。

名称= “items_name []”

name =“items_additional []”

//no need to place count in it, it will be indexed on submit if you give 
it type array    

//then do:

$data = [];

foreach($_POST['names'] $index=>$value){

 $data[] = [

    'name'=>$value,

    'additional_items'=>$_POST['items_additional][$index],

    ....
 ];

}

尝试清理代码： var y = 1; var x = 1;

$('#add-new-item').on('click', function(e){


    var html = '<div class="row"> <h3 class="item_count">Item <span class="item_number">'+ x +'</span> <i class="fa fa-close remove-item" id=""></i></h3> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_name]" type="text" class="form-control" value="" placeholder="Item name / description *" id="" required="required" /> </div> </div> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_size]" type="text" class="form-control" value="" placeholder="Size (if applicable)" id="" /> </div> </div> <div style="clear: both;"></div> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_url]" type="text" class="form-control" value="" placeholder="Item URL *" id="" /> </div> </div> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_colour]" type="text" class="form-control" value="" placeholder="Colour (if applicable)" id="" /> </div> </div> <div style="clear: both;"></div> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_additional_instructions]" type="text" class="form-control" value="" placeholder="Additional instructions (e.g. Please gift wrap, one of each colour) " id="" /> </div> </div> <div class="col-md-6"> <div class="form-group"> <input name="personal_shopper['+y+'][item_quantity]" type="text" class="form-control" value="" placeholder="Quantity *" id="" required="required" /> </div> </div> <div style="clear: both;"></div> </div>';

    $('#item-main-wrap').append(html);

    y++; 

});

这只是让它变得更干净

Answer 2

请在此处找到代码：http://phpfiddle.org/main/code/g59b-4vq2稍微修改一下提供的代码。

但它有一个错误： jQuery（'＃item-main-wrap'）。append（'Item'+ x +''... x永远不会被定义。

只需修复此错误，您的代码（此处提供）就可以正常运行。但是，在您提供的链接中，关联数组在第一个表单块之后未正确构建。

PHP：通过jQuery生成的动态字段无法正确获取值

2 个答案: