Question

在网页上点击按钮后，我正在对表格中的数据进行更改，但出现下一个错误：

Array
(
    [0] => Array
        (
            [0] => 07002
            [SQLSTATE] => 07002
            [1] => 0
            [code] => 0
            [2] => [Microsoft][ODBC Driver 13 for SQL Server]COUNT field incorrect or syntax error
            [message] => [Microsoft][ODBC Driver 13 for SQL Server]COUNT field incorrect or syntax error
        )

)

我已经查看了几个小时的代码，但我还没有找到错字。这是代码：

<?php
ini_set('max_execution_time', 300);
$serverName = "serverName\SQLEXPRESS";
$connectionInfo = array( "Database"=>"dataBase", "UID"=>"user", "PWD"=>"pass");
$conn = sqlsrv_connect( $serverName, $connectionInfo);

if( $conn === false ) {                                  
die( print_r( sqlsrv_errors(), true));
}

$sql1 = "DECLARE @a INT ". PHP_EOL;
$sql1 .= "SELECT @a = condLot FROM productos WHERE prodID = ? ". PHP_EOL;
$sql1 .= "IF (@a > 0) ". PHP_EOL;
$sql1 .= "UPDATE productos SET estadoAl = (estadoAl + 1), condLot = (condLot - 1) FROM productos WHERE prodID = ? ". PHP_EOL;
$sql1 .= "ELSE ". PHP_EOL;
$sql1 .= "UPDATE productos SET estadoAl = (estadoAl + 1) FROM productos WHERE prodID = ? ". PHP_EOL;
$var = array($_GET["idProd"]);


$stmt1 = sqlsrv_query( $conn, $sql1, $var);
if( $stmt1 === false ) {
    die( print_r( sqlsrv_errors(), true));
}

Answer 1

更新查询没有from条款。请尝试以下代码。

$sql1 .= "UPDATE productos SET estadoAl = (estadoAl + 1), condLot = (condLot - 1) WHERE prodID = ? ". PHP_EOL;

PHP内部COUNT字段不正确或语法错误

1 个答案: