我尝试使用QML TreeView模型。 Qt的例子不包括如何创建模型。我读了这个post并尝试使用@Tarod中的代码,但结果不是我的预期。
的main.cpp
#include <QGuiApplication>
#include <QQmlApplicationEngine>
#include "animalmodel.h"
#include <qqmlcontext.h>
#include <qqml.h>
int main(int argc, char *argv[])
{
QGuiApplication app(argc, argv);
AnimalModel model;
model.addAnimal("wolf", "Medium");
model.addAnimal("Bear", "Large");
QQmlApplicationEngine engine;
QQmlContext *ctxt = engine.rootContext();
ctxt->setContextProperty("myModel", &model);
engine.load(QUrl(QStringLiteral("qrc:/main.qml")));
if (engine.rootObjects().isEmpty())
return -1;
return app.exec();
}
animalmodel.h
#ifndef ANIMALMODEL_H
#define ANIMALMODEL_H
#include <QStandardItemModel>
class AnimalModel : public QStandardItemModel
{
Q_OBJECT //The Q_OBJECT macro must appear in the private section of a class definition that declares its own signals and slots or that uses other services provided by Qt's meta-object system.
public:
enum AnimalRoles {
TypeRole = Qt::UserRole + 1,
SizeRole
};
AnimalModel(QObject *parent = 0);
Q_INVOKABLE void addAnimal(const QString &type, const QString &size);
QVariant data(const QModelIndex &index, int role = Qt::DisplayRole) const;
protected:
QHash<int, QByteArray> roleNames() const;
};
#endif // ANIMALMODEL_H
animalmodel.cpp
#include "animalmodel.h"
AnimalModel::AnimalModel(QObject *parent)
: QStandardItemModel(parent)
{
}
void AnimalModel::addAnimal(const QString &type, const QString &size)
{
QStandardItem* entry = new QStandardItem();
entry->setData(type, TypeRole);
auto childEntry = new QStandardItem();
childEntry->setData(size, SizeRole);
entry->appendRow(childEntry);
appendRow(entry);
}
QVariant AnimalModel::data(const QModelIndex & index, int role) const {
QStandardItem *myItem = itemFromIndex(index);
if (role == TypeRole)
return myItem->data(TypeRole);
else if (role == SizeRole) {
if (myItem->child(0) != 0)
{
return myItem->child(0)->data(SizeRole);
}
}
return QVariant();
}
QHash<int, QByteArray> AnimalModel::roleNames() const {
QHash<int, QByteArray> roles;
roles[TypeRole] = "type";
roles[SizeRole] = "size";
return roles;
}
main.qml
import QtQuick 2.6
import QtQuick.Window 2.2
import QtQuick.Controls 1.4
ApplicationWindow {
visible: true
width: 640
height: 480
title: qsTr("Hello World")
menuBar: MenuBar {
Menu {
title: qsTr("&File")
MenuItem {
text: qsTr("&Open")
onTriggered: messageDialog.show(qsTr("Open Action Triggered"));
}
MenuItem {
text: qsTr("&Exit")
onTriggered: Qt.quit();
}
}
}
TreeView {
anchors.fill: parent
model: myModel
TableViewColumn {
title: "Name"
role: "type"
width: 300
}
TableViewColumn {
title: "Size"
role: "size"
width: 300
}
}
}
我得到的是这样的: Result
我想要的是动物类型的动物大小。
答案 0 :(得分:3)
模型子分类是Qt中最糟糕的雷区之一。建议总是让它通过模型测试(https://wiki.qt.io/Model_Test)来查看是否所有内容都已正确实现。
另一方面,在90%的情况下,您根本不需要对模型进行子类化,因为Qt提供的默认模型工作得很好。我要做的就是使用QStandardItemModel,在C ++方面,只使用QAbstractItemModel接口(即强迫自己使用QAbstractItemModel* model = new QStandardItemModel(/*parent*/);
),如果将来你觉得你真的需要重新实现模型(为了提高效率)您只需在现有代码中更改1行。
在你的情况下:
void AnimalModel::addAnimal(const QString &type, const QString &size)
{
if(columnCount()==0) insertColumn(0); // make sure there is at least 1 column
insertRow(rowCount()); // add a row to the root
const QModelIndex addedIdx = index(rowCount()-1,0);
setData(addedIdx, type, TypeRole); // set the root data
insertRow(rowCount(addedIdx),addedIdx ); // add 1 row ...
insertColumn(0,addedIdx ); // ... and 1 column to the added root row
setData(index(0,0,addedIdx), size, SizeRole); // set the data to the child
}