我有以下数据
javac 1.8.0_131
我正在尝试获取基于ID字段的唯一数据,类似于我们在通过以下查询解雇组时在MySQL中获得的数据:
ID: 1, fldname: pawan
ID: 1, fldname: pawan1
ID: 1, fldname: pawan2
ID: 2, fldname: pawan3
ID: 3, fldname: pawan4
ID: 4, fldname: pawan5
这将返回唯一值。当我们按功能使用分组时,在狮身人面像搜索中也一样。
有没有办法在elasticsearch中获取唯一值..?
以下是我的示例映射:
select * from table_name where fldname like 'pawan%' group by ID
答案 0 :(得分:0)
我建议你稍微修改你的映射:
{
"record" : {
"dynamic" : "false",
"_all" : {
"enabled" : false
},
"properties" : {
"docid" : {
"type" : "long"
},
"flgname" : {
"type" : "text"
}
}
}
}
以便docid是长
然后你可以尝试模糊查询进行过滤,再加上聚合,就像这里一样,它可以检索docid的最小值,最大值,平均值和数量:
{
"from" : 0,
"size" : 10,
"_source" : true,
"query" : {
"bool" : {
"must" : [ {
"match" : {
"flgname" : {
"query" : "pawan",
"operator" : "OR",
"fuzziness" : "1",
"prefix_length" : 1,
"max_expansions" : 50,
"fuzzy_transpositions" : true,
"lenient" : false,
"zero_terms_query" : "NONE",
"boost" : 1.0
}
}
} ]
}
},
"aggs" : {
"my_cardinality" : {
"cardinality" : {
"field" : "docid"
}
},
"my_avg" : {
"avg" : {
"field" : "docid"
}
},
"my_min" : {
"min" : {
"field" : "docid"
}
},
"my_max" : {
"max" : {
"field" : "docid"
}
}
}
}
顺便说一下,这是对您提议的数据进行上述查询的结果:
{
"took" : 47,
"timed_out" : false,
"_shards" : {
"total" : 3,
"successful" : 3,
"failed" : 0
},
"hits" : {
"total" : 6,
"max_score" : 0.9808292,
"hits" : [ {
"_index" : "stack_overflow1",
"_type" : "record",
"_id" : "40b5eac0-743b-4a6a-a06d-3ae4d56f4aca",
"_score" : 0.9808292,
"_source" : {
"docid" : "1",
"flgname" : "pawan"
}
}, {
"_index" : "stack_overflow1",
"_type" : "record",
"_id" : "27821c39-e722-4361-bc07-0dcd5181a1ad",
"_score" : 0.7846634,
"_source" : {
"docid" : "2",
"flgname" : "pawan3"
}
}, {
"_index" : "stack_overflow1",
"_type" : "record",
"_id" : "86fcd9c1-a688-4a6a-9c45-e91791a8b902",
"_score" : 0.7846634,
"_source" : {
"docid" : "4",
"flgname" : "pawan5"
}
}, {
"_index" : "stack_overflow1",
"_type" : "record",
"_id" : "fb00a3cc-f1b8-4073-8808-f2ddbc4979e2",
"_score" : 0.55451775,
"_source" : {
"docid" : "1",
"flgname" : "pawan1"
}
}, {
"_index" : "stack_overflow1",
"_type" : "record",
"_id" : "18e5e20d-17a7-4d59-b2f1-7bf325a4c4df",
"_score" : 0.55451775,
"_source" : {
"docid" : "3",
"flgname" : "pawan4"
}
}, {
"_index" : "stack_overflow1",
"_type" : "record",
"_id" : "fbf49af6-f574-4ad2-8686-cbbedc5e70c4",
"_score" : 0.23014566,
"_source" : {
"docid" : "1",
"flgname" : "pawan2"
}
} ]
},
"aggregations" : {
"my_cardinality" : {
"value" : 4
},
"my_max" : {
"value" : 4.0
},
"my_avg" : {
"value" : 2.0
},
"my_min" : {
"value" : 1.0
}
}
}
答案 1 :(得分:0)
如果你让flgname也是一个关键字,那么你可以使用子聚合来聚合over docID和subggregate over flgname。结果将类似于您提到的SQL查询。
查询看起来像:
{ "size": 0,
"query": {
"regexp":{
"flgname": "pawa.*"
}
},
"aggs" : {
"docids": {
"terms": {"field": "docid"},
"aggs": { "flgnam": { "terms": {"field": "flgname"}}}}
}
}