Question

我已经写了这个php处理程序，用于将文件上传到我的服务器。它在我进行一些测试时起作用，现在它突然出现错误。

这是错误：

警告：implode（）：参数必须是第7行的/path/to/file/upload.php中的数组

警告：implode（）：参数必须是第12行的/path/to/file/upload.php中的数组

这是我的经纪人：

<?php

error_reporting( E_ALL );
ini_set( 'display_errors', 1 );

$target_dir = "uploads/";
$target_file = $target_dir . implode( $_FILES[ "upload" ][ "name" ] );
$uploadOk = 1;
$FileType = ( pathinfo( $target_file, PATHINFO_EXTENSION ) );

// Check file size
if ( implode( $_FILES[ "upload" ][ "size" ] ) > 500000000000 ) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if ( $FileType != "zip" ) {
    echo "Sorry, only ZIP files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ( $uploadOk == 0 ) {
    echo "Sorry, your file was not uploaded.";
    // if everything is ok, try to upload file
} else {
    if ( move_uploaded_file( implode( $_FILES[ "upload" ][ "tmp_name" ] ),  $target_file ) ) {
        echo "The file " . implode( $_FILES[ "upload" ][ "name" ] ) . " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}
?>

这是我的表格：

<form action="upload.php" method="post" enctype="multipart/form-data">
    <input name="upload" type="file"/>
    <input type="submit" value="Upload"/>
</form>

我无法理解当我不碰它时如何停止工作。任何想法为什么它不起作用？

Answer 1

试试这个。
删除了不应该存在的所有内爆。

<?php

error_reporting( E_ALL );
ini_set( 'display_errors', 1 );

$target_dir = "uploads/";
$target_file = $target_dir . $_FILES[ "upload" ][ "name" ] ;
$uploadOk = 1;
$FileType = ( pathinfo( $target_file, PATHINFO_EXTENSION ) );

// Check file size
if ( $_FILES[ "upload" ][ "size" ]  > 500000000000 ) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if ( $FileType != "zip" ) {
    echo "Sorry, only ZIP files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ( $uploadOk == 0 ) {
    echo "Sorry, your file was not uploaded.";
    // if everything is ok, try to upload file
} else {
    if ( move_uploaded_file($_FILES[ "upload" ][ "tmp_name" ] , $target_file ) ) {  
        echo "The file " . $_FILES[ "upload" ][ "name" ]  . " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}
?>

Answer 2

$ _ FILE ['upload'] ['name']是一个字符串你不能内爆它

如果你想要它的名字你不必破坏它只需使用

  fileName = $_FILE['upload']['name'];
  $targDir = "uploads/";
  $tagFile = $tagDir.$fileName

会这样做

PHP文件上传抛出错误

2 个答案: