Question

我想迭代所有非空的Excel表格来获取标题。我必须使用PyExcel。这是我的代码：

import pyexcel as pe
book = pe.get_book(file_name="Mydata.xlsx")




j=0
print(j)
for j in range(100):
    for item in book.sheet_by_index(j):

     sheet = pe.get_sheet(file_name="Mydata.xlsx")
     sheetheaders= sheet.row_at(0)
     header_list = [i for i in sheetheaders if i != '' ]

     print(header_list)
     j=j+1

任何人都可以通过告诉我如何迭代它而不会出现以下错误来帮助我？

Traceback (most recent call last):
   line 11, in <module>
    for sheet in book[i]:
TypeError: 'NoneType' object is not iterable

谢谢！

Answer 1

您不需要在for循环中手动递增索引。请尝试以下代码：

for sheet_index in range(book.number_of_sheets()):
    sheet = book.sheet_by_index(sheet_index)
    header_list = [header for header in sheet.row_at(0)]

    print(header_list)

Answer 2

请试试这个：

import pyexcel as p

header_list = [[ a_header for a_header in sheet.row[0] if a_header] for sheet in p.get_book(file_name="my file.xlsx") if sheet.number_of_rows() > 0]

在python中迭代Pyexcel中的工作表

2 个答案: