我试图在我的服务器上发布文件,因为它会被直接连接,所以我做了api调用,但是我在做的时候遇到了这个错误。我不知道我哪里出错了
这是我的代码
app.directive('fileModel',fileupload);
fileupload.$inject = ['$http','$parse'];
function fileupload ($http,$parse) {
return {
restrict: 'A',
link: function(scope, element, attrs,$http) {
var model = $parse(attrs.fileModel);
var modelSetter = model.assign;
element.bind('change', function(){
scope.$apply(function($http){
modelSetter(scope, element[0].files[0]);
var fd = new FormData();
fd.append('file', element[0].files[0]);
fd.append('id', user_id);
var uploadUrl = "https://******/routes/contactRoute.php?action=upload";
$http.post(uploadUrl, fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
}).
then(function successCallback(response) {
console.log(response)
}, function errorCallback(response) {
console.log(response)
});
});
});
}
};
}
答案 0 :(得分:3)
从$http
功能中删除link
。它不需要
app.directive('fileModel',fileupload);
fileupload.$inject = ['$http','$parse'];
function fileupload ($http,$parse) {
return {
restrict: 'A',
link: function(scope, element, attrs) {
var model = $parse(attrs.fileModel);
var modelSetter = model.assign;
element.bind('change', function(){
scope.$apply(function($http){
modelSetter(scope, element[0].files[0]);
var fd = new FormData();
fd.append('file', element[0].files[0]);
fd.append('id', user_id);
var uploadUrl = "https://******/routes/contactRoute.php?action=upload";
$http.post(uploadUrl, fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
}).
then(function successCallback(response) {
console.log(response)
}, function errorCallback(response) {
console.log(response)
});
});
});
}
};
}
修改1:您还需要从$http
回调中移除$apply
。您不需要将$ http传递给任何其他内部函数。它已经注入并可用于所有其他内部方法。
scope.$apply(function(){}