Question

我是编程新手，几周前就开始使用android。

public class MainActivity extends AppCompatActivity {

int a,i,j,k;
 /*char [][] s1= new char[][]
 {
                                     {'A','B','C','D'},
                                     {'E','F','G','H'},
                                     {'I','J','K','L'},
                                     {'M','N','O','P'},
                                     {'Q','R','S','T'},
                                     {'U','V','W','X'},
                                     {' ','Y','Z',' '}};*/


char [][] s2=new char[8][8];
char[][] s3=new char[8][8];
int[] getlist=  new int[10];;
char choice,choice1;
int x,b,c,d;
String[] messageText = new String[10];
String[] messageEdit = new String[10];

public void letterNo(View view) { // Method to show screen for getting number of letters

    setContentView(R.layout.displaylettersno);
}

public void getNumber(View view) { // Method to get Numbers of Letter


    EditText et = (EditText) findViewById(R.id.editText);
    String s = et.getText().toString();
    x = Integer.parseInt(s);


    if (x > 0 && x < 9) {

        et.setText("");
    } else {

        Toast.makeText(getApplicationContext(), "Wrong Entery... Enter again", Toast.LENGTH_LONG).show();

    }
    setContentView(R.layout.gettingcolumnno);



   // Toast.makeText(getApplicationContext(),"Click on Column No in Which 1st Letter Appear",Toast.LENGTH_LONG).show();
    TextView textView = (TextView) findViewById(R.id.textView8);
for (i = 0; i < x; i++){
    textView.setText("Enter Column No. in which Your letters of name is 
present:" );
}
}


public void buttondone(View view) {
   EditText op  = (EditText) findViewById(R.id.operator2);
    String num = op.getText().toString();


    for (i = 0; i < x; i++)
    {

        getlist[i] = Integer.parseInt(String.valueOf(op.getText()));

    }

    Toast.makeText(getApplicationContext(), "Inserted", Toast.LENGTH_LONG).show();
}

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
}


}

我想开发一个名称猜猜游戏 1-它会要求用户输入号码。他认为的信件 2-它会要求用户输入他的信件所在的列号（我想根据用户的运行输入字母的编号）。假设用户输入4位数字，它将要求输入4次列。同样它有一个编辑框，用户输入列号。我为此目的使用循环，但它只显示1次我被困在这里1周。如果你明白我想要做什么，请帮助我。以下是我的代码

Answer 1

完成按钮必须按下字母时间才能获得列。

<button ion-item  (click)="goToDrivePage()">

使用for循环在Interger数组中获取值

1 个答案: