我有一个捆绑包存放在私有Satis存储库中,因为它的实体和存储库在多个应用程序之间共享。
使用该捆绑包的其余应用程序是Symfony 2.7和2.8应用程序。我正在开发一个新的应用程序,要求是使用Symfony 3.3。
在symfony 3.3应用程序中,我在我的services.yml中试过这个:
# Learn more about services, parameters and containers at
# http://symfony.com/doc/current/service_container.html
parameters:
#parameter_name: value
services:
# default configuration for services in *this* file
_defaults:
autowire: true
autoconfigure: true
# this means you cannot fetch services directly from the container via $container->get()
# if you need to do this, you can override this setting on individual services
public: false
# makes classes in src/AppBundle available to be used as services
# this creates a service per class whose id is the fully-qualified class name
CbmLtd\UvmsBundle\:
resource: '../../vendor/cbmltd/uvms-bundle/*'
exclude: '../../vendor/cbmltd/uvms-bundle/{Entity,Repository}'
UvmsApiV1Bundle\:
resource: '../../src/UvmsApiV1Bundle/*'
exclude: '../../src/UvmsApiV1Bundle/{Entity,Repository}'
上面给出了以下例外:
无法自动装配服务“UvmsApiV1Bundle \ Service \ DealerService”:方法“__construct()”的参数“$ repository”引用类“CbmLtd \ UvmsBundle \ Repository \ DealerRepository”但不存在此类服务。它不能自动注册,因为它来自不同的根命名空间。
好的,所以我想我需要明确地将此存储库声明为服务。我在Symfony 3.3文档中找不到有关将存储库声明为服务的内容,2.8语法也不起作用。
我将此添加到我的services.yml:
services:
...
CbmLtd\UvmsBundle\DealerRepository:
class: CbmLtd\UvmsBundle\Entity\DealerRepository
factory_service: doctrine.orm.entity_manager
factory_method: getRepository
arguments:
- CbmLtd\UvmsBundle\Entity\Dealer
但我仍然得到这个例外:
无法自动装配服务“UvmsApiV1Bundle \ Service \ DealerService”:方法“__construct()”的参数“$ repository”引用类“CbmLtd \ UvmsBundle \ Repository \ DealerRepository”但不存在此类服务。它不能自动注册,因为它来自不同的根命名空间。
我无法对CbmLtd \ UvmsBundle进行任何更改,因为它被多个应用程序使用。任何帮助,将不胜感激。我真的花了好几个小时,这非常令人沮丧。
答案 0 :(得分:5)
我能够使用以下services.yml:
执行此操作services:
# default configuration for services in *this* file
_defaults:
autowire: true
autoconfigure: true
# this means you cannot fetch services directly from the container via $container->get()
# if you need to do this, you can override this setting on individual services
public: false
# makes classes in src/AppBundle available to be used as services
# this creates a service per class whose id is the fully-qualified class name
CbmLtd\UvmsBundle\:
resource: '../../vendor/cbmltd/uvms-bundle/*'
exclude: '../../vendor/cbmltd/uvms-bundle/{Entity,Repository}'
CbmLtd\UvmsBundle\Repository\DealerRepository:
factory: doctrine.orm.entity_manager:getRepository
arguments:
- CbmLtd\UvmsBundle\Entity\Dealer
UvmsApiV1Bundle\:
resource: '../../src/UvmsApiV1Bundle/*'
exclude: '../../src/UvmsApiV1Bundle/{Entity,Repository}'
我不得不稍微改变我的控制器,但它现在正在工作。
答案 1 :(得分:1)
2018+和Symfony 3.3+回答
您可以更进一步,使用Repositories as Services。
这样你就可以在服务配置中使用Symfony的自动装配和简单配置。
services:
_defaults:
autowire: true
autoconfigure: true
CbmLtd\UvmsBundle\:
resource: '../../vendor/cbmltd/uvms-bundle/*'
exclude: '../../vendor/cbmltd/uvms-bundle/{Entity}'
UvmsApiV1Bundle\:
resource: '../../src/UvmsApiV1Bundle/*'
exclude: '../../src/UvmsApiV1Bundle/{Entity}'
namespace CbmLtd\UvmsBundle\Repository\DealerRepository;
final class DealerRepository
{
/**
* @var Doctrine\ORM\EntityRepository
*/
private $repository;
public function __construct(EntityManagerInterface $entityManager)
{
$this->repository = $entityManager->getRepository(Dealer::class);
}
public function find($id)
{
return $this->repository->find($id);
}
}
答案 2 :(得分:-1)
尝试更改存储库服务声明
your_bundle.your_entity_repository:
class: Doctrine\ORM\EntityRepository
factory: ['@doctrine.orm.default_entity_manager', getRepository]
arguments:
- YourBundle\Entity\YourEntity
然后通过引用它来注入repo:
your_bundle.your_service:
class: YourBundle\Service\YourService
arguments:
- "@your_bundle.your_entity_repository"
calls:
- [setContainer, ['@service_container']]
答案 3 :(得分:-1)
您的服务声明中有拼写错误,您忘记了“存储库”命名空间。此外,该类是位于“实体”还是“存储库”中?服务标识应与实际的完全限定类名相同。在services.yml中,尝试:
CbmLtd\UvmsBundle\Repository\DealerRepository:
class: CbmLtd\UvmsBundle\Repository\DealerRepository
而不是:
CbmLtd\UvmsBundle\DealerRepository:
class: CbmLtd\UvmsBundle\Entity\DealerRepository