使用Idris观察类型驱动开发的练习9.2:
data Last : List a -> a -> Type where
LastOne : Last [value] value
LastCons : (prf : Last xs value) -> Last (x :: xs) value
Uninhabited (Last [] value) where
uninhabited LastOne impossible
uninhabited (LastCons _) impossible
notLast : Not (x = value) -> Last [x] value -> Void
notLast prf LastOne impossible
notLast prf (LastCons _) impossible
isLast : DecEq a => (xs : List a) -> (value : a) -> Dec (Last xs value)
isLast [] value = No absurd
isLast (x::[]) value = case decEq x value of
Yes Refl => Yes LastOne
No contra => No (notLast contra)
isLast (x::y::ys) value = ?rhs
我在notLast prf LastOne
案例中遇到编译时错误:
*section1> :r
Type checking ./section1.idr
section1.idr:20:9:notLast prf LastOne is a valid case
Holes: Main.rhs, Main.notLast
为什么编译器认为它是一个有效的案例?
答案 0 :(得分:4)
Idris无法看到Not (value = value)
与Void
同构,因此您需要通过解释问题所在来帮助它:
notLast : Not (x = value) -> Last [x] value -> Void
notLast prf LastOne = absurd (prf Refl)
notLast prf (LastCons _) impossible