在JSP页面

Question

我尝试使用Spring MVC进行Web应用程序，当我尝试使用对象信息填充JSP页面时，我遇到了困难：

我有一个Pessoa课（＆＃34; Person＆＃34;）：

@Entity
public class Pessoa {
    @Id @GeneratedValue(strategy=GenerationType.IDENTITY)
    private int idPessoa;
    private String nome;
    private int rg;
    private TipoEstado rgEstado;
    private int cpf;
    @DateTimeFormat
    private Calendar dataNascimento;
    private String profissao;
    private String nomePai;
    private String nomeMae;
    private TipoEstadoCivil estadoCivil; //enum
    private TipoSituacao situacao; 

    @OneToOne(cascade=CascadeType.ALL, fetch = FetchType.LAZY)
    @JoinColumn(name="idEndereco")
    private Endereco endereco;

    @OneToMany(mappedBy = "pessoa", targetEntity = ContaCorretora.class, fetch = FetchType.LAZY, cascade = CascadeType.ALL)
    private List<ContaCorretora> contaCorretora;

    @OneToMany(mappedBy = "pessoa", targetEntity = Telefone.class, fetch = FetchType.LAZY, cascade = CascadeType.ALL)
    private List<Telefone> telefone;

    @OneToOne(cascade=CascadeType.ALL, fetch = FetchType.LAZY)
    @JoinColumn(name="idContaBancaria")
    private ContaBancaria contaBancaria;

    @OneToOne(cascade=CascadeType.ALL, fetch = FetchType.LAZY)
    @JoinColumn(name="email")
    private Usuario usuario;

控制器方法：

@RequestMapping("/listarPessoa/{id}") 
public ModelAndView listarPessoa(@PathVariable("id") int id) {
    ModelAndView modelAndView = new ModelAndView("pessoa/listaespecifica");
    Pessoa pessoa = pessoaDao.find(id);
    modelAndView.addObject("pessoa",pessoa);
    return modelAndView;
}

PessoaDAO方法：

public Pessoa find(int id) {        
    return manager.createQuery("select p from Pessoa as p where p.idPessoa = :id", Pessoa.class)
            .setParameter("id", id).getSingleResult();
}

主要问题是，当attribut有关系时，我无法在.JSP页面中显示信息。当我把属性没有关系时，它工作正常！

例如：

以上代码有效：

<tr>
    <td><b>RG</b></td>
    <td>${pessoa.rg }</td>
</tr>

当我把这样的代码放在一起时，不起作用：（＆＃34; Endereco＆＃34;就像＆＃34;地址＆＃34;，在这种情况下是与pessoa的OnetoOne关系，＆＃ 34; logradouro＆＃34;是Endereco的一个属性＆＃34;。然后，上面的代码不起作用：

<tr>
    <td><b>Endereco</b></td>
    <td>${pessoa.endereco.logradouro }</td>
</tr>

这是错误：

**type Exception report
message An exception occurred processing JSP page /WEB-INF/views/pessoa/listaespecifica.jsp at line 69
description The server encountered an internal error that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: An exception occurred processing JSP page /WEB-INF/views/pessoa/listaespecifica.jsp at line 69
66:     </tr>
67:     <tr>
68:             <td><b>Endereco</b></td>
69:             <td>${pessoa.endereco.logradouro }</td>
70: 
71: 
72:     </tr>**

Answer 1

将Endereco endereco的获取类型更改为渴望。喜欢这个

@OneToOne(cascade=CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name="idEndereco")
private Endereco endereco;