我看了this SO question和that one,但仍然无法解决我的问题。我有以下data.table,其中只包含我的data.table的总列和行的几个。
library(data.table)
structure(list(Patient = c("MB108", "MB108", "MB108", "MB108",
"MB108", "MB108", "MB108", "MB108", "MB108", "MB108"), Visit = c(1,
1, 1, 1, 9, 9, 9, 9, 12, 12), Stimulation = c("NC", "SEB", "PPD",
"E6C10", "NC", "SEB", "PPD", "E6C10", "NC", "SEB"), `CD38 ` = c(83.3,
63.4, 83.2, 91.5, 90.9, 70.9, 71, 88.4, 41.7, 47.9)), .Names = c("Patient",
"Visit", "Stimulation", "CD38 "), class = c("data.table", "data.frame"
), row.names = c(NA, -10L), .internal.selfref = <pointer: 0x102806578>)
我想在第4列进行t.test,当访问次数为1时,访问次数为9次。 我检查了NAs以及两列的长度。
感谢您的帮助!
#na.omit(boolean_dt3)
#print(length(unlist(boolean_dt3[Visit== 1,4, with = FALSE])))
#print(length(unlist(boolean_dt3[Visit== 9,4, with = FALSE])))
wilcox.test( unlist(boolean_dt3[Visit== 1,4, with = FALSE])~ unlist(boolean_dt3[Visit== 9,4, with = FALSE]) , paired = T, correct=FALSE)
答案 0 :(得分:5)
我刚认为,
而不是~
适用于我的问题。
答案 1 :(得分:1)
以下是column 4
Value
分组进行wilcoxon测试的方法
library(dplyr)
wilcox.test( filter(df, Visit==1)$CD38, filter(df, Visit==9)$CD38, paired=TRUE)
答案 2 :(得分:0)
尝试这个表述:
wilcox.test(numeric_var ~ two_level_group_var)