我已经创建了一个登录表单,用于比较从文本文件输入的用户名和密码,然后显示用户名/密码是否不正确或是否允许访问。
<form role="form" action="/traveositelogin" method="post">
<div class="form-group">
<label class="sr-only" for="form-username">Username</label>
<input type="text" placeholder="Username..." class="form-username form-control" id="username">
<p id="UsernameIncorrect" hidden>Incorrect Username. Try Again</p>
</div>
<div class="form-group">
<label class="sr-only" for="form-password">Password</label>
<input type="password" placeholder="Password..." class="form-password form-control" id="password">
<P id="PasswordIncorrect" hidden>Incorrect Password. Try Again.</p>
</div>
<button type="submit" class="btn" id="Login">Login</button>
<p><a href="contact.html"> Forgot Password?</a></p>
<div class="form-group">
</div>
这是我的servlet代码:
package com.traveosoft;
import java.io.IOException;
import java.util.Properties;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.Scanner;
import java.io.FileInputStream;
import java.io.InputStreamReader;
public class TraveoWebsiteLoginServlet extends HttpServlet {
@Override
public void doGet(HttpServletRequest req, HttpServletResponse resp)
throws IOException {
resp.setContentType("text/plain");
resp.getWriter().println("Hello, this is a testing servlet. \n\n");
Properties p = System.getProperties();
p.list(resp.getWriter());
}
public void doPost(HttpServletRequest req, HttpServletResponse resp)
throws IOException {
String filePath = "{login.txt}";
String username = null;
String password = null;
//resp.setContentType("text/plain");
//resp.getWriter().println("Hello, this is a testing servlet. Post method \n\n");
//Properties p = System.getProperties();
//p.list(resp.getWriter());
if (req.getParameter("Login")!= null )
{
username = req.getParameter("username");
password = req.getParameter("password");
//resp.sendRedirect("index.html");
}
try
{
FileInputStream fstream = new FileInputStream("login.txt");
// Use DataInputStream to read binary NOT text.
BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
String strLine;
int count = 0;
while((strLine = br.readLine())!= null)
{
//Enter userName
String[] creds = strLine.split(",");
System.out.println("creds[0], creds[1]:" + creds[0] + "," +creds[1] );
//System.out.println("User name from the file is:"+ creds[0]);
if (creds[0].equals(username))
{
//user name matches. So we need to check for password now
count++;
if (creds[1].equals (password))
{
//Great... password also matches. Allow the user access to our repository
System.out.println("Allow access");
}
else
{
// Password didn't match. Ask the user to reenter the password
System.out.println("Wrong password. Try Again.");
}
break;
}
//strLine = br.readLine();
//count++;
//Enter Password
//System.out.println("Password from the file is:"+ creds[1]);
}
if (count == 0 )
{
// No user name matched with the user name entered by the user. So user name itself is wrong
System.out.println("Your user name is wrong. Try Again.");
}
fstream.close();
br.close();
}
catch (Exception e)
{
System.err.println("Error: " + e.getMessage());
}
}
}
如何编写javascript代码,当用户名错误时,打印“用户名错误”;密码错误,然后打印“密码错误”;如果两者都正确,允许我将超链接引用放到保存资源的页面。
我很欣赏javascript中的示例代码(而不是jsp文件)。我还在学习这一切,任何帮助都会非常感激。在此先感谢。
答案 0 :(得分:0)
如果我理解正确,您希望将响应对象(或说消息)从服务器端直接发送到客户端,而不是通过JSP发送它。
为了做到这一点,你需要做更多的努力...
您可以按照以下步骤操作:
1.创建响应对象
2.将该对象转换为JSON格式
3.将您的响应内容类型设置为text / json并设置响应。
//要发送给JavaScript的响应对象
public class ResponseMessage {
private boolean isLoginSuccess;
private String errorMessage;
// Getters and setters ...
}
// Servlet code
ResponseMessage message = new ResponseMessage();
message.setError(true);
message.setErrorMessage("Your error message");
Gson gson = new Gson(); // GSON: library to convert Java object to JSON
String content = gson.toJson(message);
response.setContentType("text/json");
response.getWriter().print(content);
JS代码
function processRequest() {
var result = jQuery.ajax ({
url: "your.url",
method: "post",
async: false,
data: ""
});
// Create JS object from JSON
var message = jQuery.parseJSON(result.responseText);
// Now you can show your message
if(message.isLoginSuccess) {
alert("Welcome");
}else{
alert("Login Failed");
}
}