我想根据值对整行应用颜色突出显示,并保留rhandsontable的复选框功能。在下面的简单示例中,我希望第3行为粉红色,第4行为绿色。
library(rhandsontable)
DF = data.frame( bool = TRUE,val = 1:10, big = LETTERS[1:10],
small = letters[1:10],
stringsAsFactors = FALSE)
###Checkboxes not Present/Entire row not highlighted
rhandsontable(DF, readOnly = FALSE, width = 750, height = 300) %>%
hot_cols(renderer = "
function (instance, td, row, col, prop, value, cellProperties) {
Handsontable.renderers.NumericRenderer.apply(this, arguments);
if (value == 'C') {
td.style.background = 'pink';
} else if (value == 'D') {
td.style.background = 'green';
}
}")
####Checkboxes Present
rhandsontable(DF, readOnly = FALSE, width = 750, height = 300)
答案 0 :(得分:1)
问题是您使用NumericRenderer尝试将应用的列转换为数字。我的解决方案可能不是最优的,但它可以完成这项工作。
library(rhandsontable)
DF = data.frame( bool = TRUE,val = 1:10, big = LETTERS[1:10],
small = letters[1:10],
stringsAsFactors = FALSE)
# Text Renderer
text_renderer <- "
function (instance, td, row, col, prop, value, cellProperties) {
Handsontable.renderers.TextRenderer.apply(this, arguments);
# This is the column which you want to check for coloring
var col_value = instance.getData()[row][2]
if (col_value == 'C') {
td.style.background = 'pink';
} else if (col_value == 'D') {
td.style.background = 'green';
}
}"
# Renderer for the bool column
bool_renderer <- "
function (instance, td, row, col, prop, value, cellProperties) {
Handsontable.renderers.CheckboxRenderer.apply(this, arguments);
var col_value = instance.getData()[row][2]
if (col_value == 'C') {
td.style.background = 'pink';
} else if (col_value == 'D') {
td.style.background = 'green';
}
}
"
# Entire row highlighted and checkbox attribute preserved
rhandsontable(DF, readOnly = FALSE, width = 750, height = 300) %>%
hot_col(col = c(2, 3, 4), renderer = text_renderer) %>%
hot_col("bool", renderer = bool_renderer)
诀窍是你创建了两个渲染器:
instance.getData()[row][2]
检索行索引row
处的大列值。因此,渲染器检查每一行if语句中的条件是否为TRUE。
干杯