Question

我试图处理异常

这是堆栈跟踪;

org.hibernate.exception.ConstraintViolationException: could not execute statement
    at org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:59)
    at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:42) 
    ...
    ...
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source)
    at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
    at java.lang.Thread.run(Unknown Source)
Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException: Duplicate entry 'testemail@gmail.com' for key 'UK_n7ihswpy07ci568w34q0oi8he'

当我尝试使用getMessage（）方法获取messsase时，消息get是来自ConstraintViolationException的“无法执行语句”，

但我想要的是获得 “来自MySQLIntegrityConstraintViolationException的密钥'UK_n7ihswpy07ci568w34q0oi8he'”重复输入'testemail@gmail.com'。

这是我的捕捉过程

catch(MySQLIntegrityConstraintViolationException e){
    e.printStackTrace();
    message = "MySQLIntegrity,\n Duplicate Entry, \n" + e.getMessage();
}
catch(ConstraintViolationException e){
    e.printStackTrace();
    message = "ConstraintViolation,\n Duplicate Entry, \n" + e.getMessage();
}
catch (Exception e) {
    e.printStackTrace();
    message = "Exception rule,\n" + e.getMessage();
}

Answer 1

尝试

catch(ConstraintViolationException e){
    e.printStackTrace();
    message = "ConstraintViolation,\n Duplicate Entry, \n" + e.getCause().getMessage();
}

引起： com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException：重复条目'testemail@gmail.com'，用于键'UK_n7ihswpy07ci568w34q0oi8he'

这是原始异常

简单变体：

private String getRootCauseMessage(Throwable ex){
    if(ex.getCause() == null){
        return ex.getMessage();
    }
    return getRootCauseMessage(ex.getCause());
}

或

Throwable cause = originalException;
while(cause.getCause() != null) {
    cause = cause.getCause();
}

但由于它是简单的变体，它们可能会转到无穷大recursio.you可以添加一些计数器并计算递归调用。如果它更多100返回空字符串

如果您有权访问apache commons，请使用它。 http://commons.apache.org/proper/commons-lang/apidocs/src-html/org/apache/commons/lang3/exception/ExceptionUtils.html，有getRootCause方法可以为你提供根异常，你可以从一个/

获得masseage

如何在hibernate中获取MySQLIntegrityConstraintViolationException消息

1 个答案: