Question

我正在尝试使用TLSharp发送消息但不能，我不会收到错误，只是执行代码而什么都不做;

这是我的方法。

public virtual async Task SendMessageTest()
        {
            string NumberToSendMessage = "+55199999999";
            if (string.IsNullOrWhiteSpace(NumberToSendMessage))
                throw new Exception("TESTE");

            // this is because the contacts in the address come without the "+" prefix
            var normalizedNumber = NumberToSendMessage.StartsWith("+") ?
                NumberToSendMessage.Substring(1, NumberToSendMessage.Length - 1) :
                NumberToSendMessage;

            var client = NewClient();
            var tsk = client.ConnectAsync();
            await client.ConnectAsync();


            var result = await client.GetContactsAsync();

            var user = result.users.lists
                .OfType<TLUser>()
                .FirstOrDefault(x => x.phone == normalizedNumber);

            if (user == null)
            {
                throw new System.Exception("Number was not found in Contacts List of user: " + NumberToSendMessage);
            }

            await client.SendTypingAsync(new TLInputPeerUser() { user_id = user.id });
            Thread.Sleep(3000);
            await client.SendMessageAsync(new TLInputPeerUser() { user_id = user.id }, "TEST");
        }

这是我的代码，是说等待激活，我该怎么办？

我也试图使用这种方法，但它也没有返回任何东西。我是TelegramApi的新手，我做错了什么？

await client.ConnectAsync();

Answer 1

你应该先授权！只有在那之后你才能调用其他方法。看at the examples here。

一般来说，你应该写这样的东西：

public static void main(String[] args) {
    double avg = Arrays.stream(new int[]{1,3,2,5,8}).average().getAsDouble();

    System.out.println("avg: " + avg);
}

使用TLSharp测试连接

1 个答案: