Question

如何将命令行参数传递给使用＆＃39; invoke-command＆＃39;调用的会话？在powershell 2.0中

我的剧本：

param(
    [string]$hostname = 'my_server_name'
)

function createSession($hostname){
    return New-PSSession -ComputerName $hostname -Credential $env:UserDomain\$env:UserName
}
$session = createSession $hostname
invoke-command -Session $session -ScriptBlock {
   write-host $hostname
   write-host $using:hostname
   write-host $script:hostname 
   write-host '**test text**'

}
    Exit-PSSession

输出:(如果我直接打印参数值，我会得到空字符串。）

**test text**

Answer 1

param(
    [string]$hostname = 'my_server_name'
)

function createSession($hostname){
    return New-PSSession -ComputerName $hostname -Credential $env:UserDomain\$env:UserName
}
$session = createSession $hostname
invoke-command -Session $session -ScriptBlock {
$hostname=$using:hostname

or

$hostname=$script:hostname
   write-host $hostname
   write-host '**test text**'

}
    Exit-PSSession

希望以上任何一个有所帮助，如果不是请在powershell中查看范围变量的概念，可能会有所帮助 Powershell variable scoping

Answer 2

使用param block

$hostname = $env:computername
Invoke-Command -ScriptBlock { param($hostname)
    Write-OutPut $hostname
} -ArgumentList $hostname

如何在PowerShell 2.0中将命令行参数传递给调用的会话

2 个答案: