Question

如果这是一个重复的问题，我很抱歉。我花了一个小时的时间试图找到答案，并测试了一些没有成功的理论。如果不发布我正在处理的整个代码，我就会发布代码片段。

基本上我需要将这些for循环语句打印成一行来为每个员工运行。

即。＆＃39;员工Sam今年31岁，他们的职位是数据分析师，他们每年赚90,000美元。他们2017年的奖金为2,700美元。＆＃34;

# Employee List
names = ['Sam', 'Chris', 'Jose', 'Luis', 'Ahmad']
ages = ['31', '34', '30', '28', '25']
jobs = ['Data Analyst', 'SEO Python Genius', 'Data Analyst', 'Interchange 
Analyst', 'Data Analyst']
salaries = ['$90,000', '$120,000', '$95,000', '$92,000', '$90,000']
bonuses = ['$2,700', '$3,600', '$2,850', '$2,750', '$2,700']


# this for-loop goes through name list
for name in names:
    print ("Employee %s" % name)

for age in ages:
    print ("is %s" % age, "years old")

for job in jobs:
    print (", their job title is %s" % job)

for salary in salaries:
    print (" and they make %s" % salary, "annually.")

for bonus in bonuses:
    print ("Their 2017 bonus will be %s." % salary)

Answer 1

您可以使用zip通过并行列表进行集体迭代。

for name, age, job, salary, bonus in zip(names, ages, jobs, salaries, bonuses):
    print ("Employee %s" % name)
    print ("is %s years old" % age)
    print (", their job title is %s" % job)
    print (" and they make %s annually" % salary)
    print ("Their 2017 bonus will be %s." % bonus)

这仍然是消息的每个部分在一个单独的行上，因为它们是单独的打印语句。相反，您可以将它们合并为一个print：

for name, age, job, salary, bonus in zip(names, ages, jobs, salaries, bonuses):
    print ("Employee %s is %s years old. Their job title is %s, and "
           "they make %s annually. Their 2017 bonus will be %s."
           %(name, age, job, salary, bonus))

Answer 2

zip这些在一起，理想情况下，使用格式字符串来减少整行，因为它们都使用相同的格式：

emps = zip(names, ages, jobs, salaries, bonuses)
fmt = ("Employee {} is {} years old, their job " 
       "title is {} and they make {} annually. " 
       "Their 2017 bonus will be {}.")
for emp in emps:
    print(fmt.format(*emp))

相应地调整fmt中的格式。

Answer 3

如果您确定所有列表都具有相同的长度，您也可以按索引访问列表。

for i in range(len(names)):
    print(names[i], ages[i], jobs[i], salaries[i], bonuses[i])

与使用zip相比，我个人认为这使代码的可读性降低。

for循环使用多个列表在Python 3中创建一个语句

3 个答案: