Question

我有一个关于显示另一个数组的数组中的变量的问题。以下是var_dump()变量$_POST的示例。正如你所看到的，我有一个数组......和该数组中的另一个数组......以及该数组中的另一个数组..我实际上需要每个层中的一个变量。

Array(
[type] => note
[date_time] => 17-01-01
[initiated_from] => admin
[initiated_by] => admin
[list] => 0
[note] => THIS IS A TEST 
[contact] => Array
    (
        [id] => 250
        [email] => TEST@TESTING.COM
        [first_name] => TEST
        [last_name] => McTESTER
        [phone] => (777)777-7777
        [ip] => 0.0.0.0
        [tags] => buyer, requote, followup1, delete
        [fields] => Array
            (
                [3] => TESTER@TESTER.com
                [5] => TESTING TESTER
                [10] => STATE
                [11] => CITY
                [12] => COUNTY
                [6] => PHONE NUMBER
                [8] => www.test.com
                [9] =>  MORE TESTS
            )

这是我尝试的代码。

$sql_note="INSERT INTO customer_notes(customer_email,note,added_by,note_date) VALUES('$_POST[contact][email]','$_POST[note]','$_POST[contact][fields][3]','$note_date')";

（忽略$note_date）所以这些是我想要的三件事......

$_POST[note]

$_POST[contact][email]

$_POST[contact][fields][3]

我得到第一个就好了，但我得到了ARRAY[EMAIL]和ARRAY[FIELDS][3]

Answer 1

您错误地使用了variable expansion：

$foo = array();
$foo['one']['two'] = 'OK';

echo "Value is $foo[one][two]\n"; // Value is Array[two]
echo "Value is {$foo[one][two]}\n"; // Value is OK

......在错误的工作中。您的查询应如下所示：

$sql_note = "INSERT INTO customer_notes(customer_email, note, added_by, note_date)
    VALUES (?, ?, ?, ?)";

...值应该在数组中传递。将原始不受信任的数据注入SQL代码非常麻烦，并且会导致SQL注入漏洞。请查看数据库库的文档。

数组中的PHP数组在数组$ _POST中

1 个答案: