使用正则表达式检索最后一次数字出现后的单词

Question

我在字符串变量中收到streetname + doorno。我必须分开他们。我当前的正则表达式是/[0-9].*$/这适用于普通地址。但我有streetname也包含数值的地址。在这种情况下，streetname也被视为doorno。

对于前，

[Correct] Street = Example Street 15B returns doorno = 15B

[Correct] Street = Example Street 15 B returns doorno = 15 B

[Correct] Street = Example Street returns doorno = null

[Correct] Street = Example Street15 returns doorno = 15

[Incorrect] Street = Example Street 158 7 returns doorno = 158 7. However I am expecting, the streetname = Example Street 158 & doorno = 7

[Incorrect] Street = Example Street 158 7 B returns doorno = 158 7 B. However I am expecting, the streetname = Example Street 158 & doorno = 7 B

[Incorrect] Street = Example Street 158 7B returns doorno = 158 7B. However I am expecting, the streetname = Example Street 158 & doorno = 7B

[Incorrect] Street = Example Street158 7 B returns doorno = 158 7B. However I am expecting, the streetname = Example Street158 & doorno = 7B

有人可以帮我修一下上述错误案例的正则表达式吗？

Answer 1

您可以使用

/^(.*\D)(\d.*)$/

匹配：

• ^ - 字符串的开头
• (.*\D) - 第1组：任何0+字符（除了换行符之外）直到最后一次出现的后续子模式（即\D\d.*$）
• (\d.*) - 第2组：一个数字，然后是任何0+字符（除了换行符之外）
• $ - 字符串结束。