我正在创建一个餐厅应用程序,用户可以在第一个屏幕上选择他们想要做的餐厅。在他们做出选择之后,用户应该按下开始按钮,它将把它带到那个视图控制器
我不知道如何开始,任何帮助将不胜感激。
答案 0 :(得分:0)
在picker didselect delegate中设置标签文本。然后按钮动作方法决定在标签文本的基础上打开哪个vc。
答案 1 :(得分:0)
使用按钮操作是完成按钮,我们使用选择器嵌入以进行最终选择。
使用以下代码:正常工作
import UIKit
class PickerViewController: UIViewController,UIPickerViewDataSource, UIPickerViewDelegate {
@IBOutlet weak var pickerVieww: UIPickerView!
var viewControllerArray = [String]()
var value = Int()
override func viewDidLoad() {
super.viewDidLoad()
pickerVieww.delegate = self
pickerVieww.dataSource = self
viewControllerArray = ["controller1","controller2","controller3"]
}
func numberOfComponents(in pickerView: UIPickerView) -> Int {
return 1
}
func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
return viewControllerArray.count
}
func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
return viewControllerArray[row]
}
func pickerView(_ pickerView: UIPickerView,didSelectRow row: Int,inComponent component: Int)
{
if(row == 0) {
value = 0
}
else if(row == 1) {
value = 1
}
else{
value = 2
}
}
@IBAction func swicthToController(_ sender: Any) {
if value == 0{
let vc = self.storyboard?.instantiateViewController(withIdentifier: "first") as! asasasViewController
self.present(vc, animated: true, completion: nil)
}
if value == 1{
let vc = self.storyboard?.instantiateViewController(withIdentifier: "second") as! secondViewController
self.present(vc, animated: true, completion: nil)
}
if value == 2{
let vc = self.storyboard?.instantiateViewController(withIdentifier: "third") as! thirdViewController
self.present(vc, animated: true, completion: nil)
}
}
}