while(true)循环强制我的应用程序在Android中崩溃

时间:2017-06-20 16:06:21

标签: java android

我正在尝试实现无限循环,因为我希望代码一次又一次地运行以下代码...但它导致我的应用程序崩溃...因为我是这个技术的初学者,我不是意识到这一点...任何帮助将不胜感激..谢谢你...

这是Logcat

  06-20 22:04:38.029 22848-22848/sensor.swapni E/AndroidRuntime: FATAL 
  EXCEPTION: main
                                                           Process: 
   sensor.swapni, PID: 22848

   java.lang.OutOfMemoryError: Failed to allocate a 13571692 byte allocation 
   with 7716072 free bytes and 7MB until OOM
                                                               at 
   java.util.ArrayList.add(ArrayList.java:118)
                                                               at 
   android.view.ViewRootImpl$RunQueue.postDelayed(ViewRootImpl.java:8656)
                                                               at 
   android.view.View.postDelayed(View.java:14275)
                                                               at 
   sensor.swapni.Second.onCreate(Second.java:54)
                                                               at 
   android.app.Activity.performCreate(Activity.java:6904)
                                                               at 

android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1136)
                                                               at 
android.app.ActivityThread.performLaunchActivity(ActivityThread.java:3266)
                                                               at 
 android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:3415)
                                                               at   
android.app.ActivityThread.access$1100(ActivityThread.java:229)
                                                               at 
android.app.ActivityThread$H.handleMessage(ActivityThread.java:1821)
                                                               at 
android.os.Handler.dispatchMessage(Handler.java:102)
                                                               at 
android.os.Looper.loop(Looper.java:148)
                                                               at 
android.app.ActivityThread.main(ActivityThread.java:7325)
                                                               at 
java.lang.reflect.Method.invoke(Native Method)
                                                               at 

这是java代码

 while(true) {
        tv1.postDelayed(new Runnable() {
            @Override
            public void run() {
                tv1.setVisibility(View.INVISIBLE);
                tv2.setVisibility(View.VISIBLE);

            }
        }, 1000);
        tv1.postDelayed(new Runnable() {
            @Override
            public void run() {
                tv2.setVisibility(View.INVISIBLE);
                tv1.setVisibility(View.VISIBLE);
            }
        }, 2000);

3 个答案:

答案 0 :(得分:3)

该循环每秒运行数千次。每次运行时,它都会向堆中添加至少4个对象(2个Runnables,2个消息到处理程序)。最终你的内存不足。

如果你想每2秒钟继续做一些事情,你可以在实际线程上调用postDelayed一次,然后在runnable中再次调用它。像这样:

   tv1.postDelayed(new Runnable() {
        @Override
        public void run() {
            tv1.setVisibility(View.INVISIBLE);
            tv2.setVisibility(View.VISIBLE);
            tv1.postDelayed(this, 1000);
        }
    }, 1000);

答案 1 :(得分:0)

很可能是内存不足问题。尝试设置一个计时器,而不是创建大量的新对象。

http://java.sun.com/javase/6/docs/api/java/util/Timer.html

答案 2 :(得分:0)

将这两种方法添加到您的班级中:

private void setVisibility1() {
    tv1.setVisibility(View.INVISIBLE);
    tv2.setVisibility(View.VISIBLE);

    tv1.postDelayed(new Runnable() {
        @Override
        public void run() {
            setVisibility2();
        }
    }, 1000);
}

private void setVisibility2() {
    tv1.setVisibility(View.VISIBLE);
    tv2.setVisibility(View.INVISIBLE);

    tv1.postDelayed(new Runnable() {
        @Override
        public void run() {
            setVisibility1();
        }
    }, 1000);
}

用一次调用此方法替换整个循环:

setVisibility1();

setVisibility1切换可见性并启动setVisibility2的计时器。执行setVisibility2时,它会再次更改可见性并启动setVisibility1的计时器。