Question

我在Oracle数据库中有一个类似于此数据的列

column1
/opt/log/data/abcd.efghi.jklmn.aaa.txt
/opt/log/data/abbbcd.efccghi.jkdsdflmn.abab.txt
/opt/log/data/nmvcnmcd.efjhjghi.jkvslmn.abcbc.txt
/opt/log/data/hjsdhj.hjfdhdf.hdfhjd.aghag.txt
/opt/log/data/dfhjfdhj.yureyer.qwtyq.hjahjh.txt

我想以这样的方式分割数据

**firstdot    seconddot      thirdnfourthdot**
abcd        efghi          jklmn.aaa
abbbcd      efccghi        jkdsdflmn.abab
nmvcnmcd    efjhjghi       jkvslmn.abcbc
hjsdhj      hjfdhdf        hdfhjd.aghag
dfhjfdhj    yureyer        qwtyq.hjahjh

我可以通过

获取seconddot值

select substr(column1,instr(column1,'.',1+1,instr(column1,'.',1,2)-instr(column1,'.',1,1)-1) as secondot

但我无法得到其余的。你能帮忙吗？

非常感谢

Answer 1

如果没有正则表达式，你需要为你需要的每个子字符串回复相同的逻辑，每个timi根据＆＃34;终止符＆＃34;的位置选择初始位置和亮度。那个子串。

/* input data */
    with yourTable(column1) as (
        select '/opt/log/data/abcd.efghi.jklmn.aaa.txt' from dual union all
        select '/opt/log/data/abbbcd.efccghi.jkdsdflmn.abab.txt' from dual union all
        select '/opt/log/data/nmvcnmcd.efjhjghi.jkvslmn.abcbc.txt' from dual union all
        select '/opt/log/data/hjsdhj.hjfdhdf.hdfhjd.aghag.txt' from dual union all
        select '/opt/log/data/dfhjfdhj.yureyer.qwtyq.hjahjh.txt' from dual
    )
/* query */
    select substr(column1, instr(column1, '/', -1) +1, instr(column1, '.') - instr(column1, '/', -1)-1) firstDot,
           substr(column1, instr(column1, '.') +1, instr(column1, '.', 1, 2) - instr(column1, '.') -1) secondDot,
           substr(column1, instr(column1, '.', 1, 2) +1, instr(column1, '.', 1, 4) - instr(column1, '.', 1, 2) -1) thirdAndFourthDot
    from yourTable

给出：

FIRSTDOT        SECONDDOT       THIRDANDFOURTHD
--------------- --------------- ---------------
abcd            efghi           jklmn.aaa
abbbcd          efccghi         jkdsdflmn.abab
nmvcnmcd        efjhjghi        jkvslmn.abcbc
hjsdhj          hjfdhdf         hdfhjd.aghag
dfhjfdhj        yureyer         qwtyq.hjahjh

以更易读的方式：

select substr(column1, lastSlashPos +1, firstDotPos - lastSlashPos -1) as firstDot,
       substr(column1, firstDotPos +1, secondDotPos - firstDotPos -1) as secondDot,
       substr(column1, secondDotPos +1, fourthDotPos - secondDotPos -1) as thirdAndFourthDot
from (
        select instr(column1, '/', -1) as lastSlashPos,
               instr(column1, '.') as firstDotPos,
               instr(column1, '.', 1, 2) as secondDotPos,
               instr(column1, '.', 1, 3) as thirdDotPos,
               instr(column1, '.', 1, 4) as fourthDotPos,
               column1
        from yourTable
     )

Answer 2

select substr('/opt/log/data/abcd.efghi.jklmn.aaa.txt',instr('/opt/log/data/abcd.efghi.jklmn.aaa.txt','/',-1) + 1) from dual;

这会在最后/

之后为您提供文字

然后，您需要对instr：

应用.

select 
  substr(text, 1,  instr(text,'.', 1) - 1), 
  substr(text, instr(text,'.', 1) + 1, instr(text,'.', 2) - 1), 
  substr(text, instr(text,'.', 2) + 1) 
from (
    select substr('/opt/log/data/abcd.efghi.jklmn.aaa.txt',instr('/opt/log/data/abcd.efghi.jklmn.aaa.txt','/',-1) + 1) text from dual
);

Oracle中的拆分列

2 个答案: