Question

我有这样的代码：

import time
import datetime
def dates():
    date1 = str(input('Date start: '))
    try:
        dt_start = datetime.strptime(date1, '%d, %m, %Y')
    except ValueError:
        print ("Incorrect format")
    date2 = str(input('Date end: '))
    try:
        dt_end = datetime.strptime(date2, '%d, %m, %Y')
    except ValueError:
        print ("Incorrect format")
    if date1 > date2:
        print("Error!")
    dates()

我想定义日期输入格式，如d.m.Y。

例如，当我输入＆＃34; 17.12.1995＆＃34;。我收到了错误： 'module' object has no attribute 'strptime'。

如何定义用户输入格式？

Answer 1

<?php try { // File_Route. $fileRoute = "/Name_folder/Name"; $fieldname = "file"; // Get filename. $filename = explode(".", $_FILES[$fieldname]["name"]); // Validate uploaded files. // Do not use $_FILES["file"]["type"] as it can be easily forged. $finfo = finfo_open(FILEINFO_MIME_TYPE); // Get temp file name. $tmpName = $_FILES[$fieldname]["tmp_name"]; // Get mime type. $mimeType = finfo_file($finfo, $tmpName); // Get extension. You must include fileinfo PHP extension. $extension = end($filename); // Allowed extensions. $allowedExts = array("gif", "jpeg", "jpg", "png", "svg", "blob"); // Allowed mime types. $allowedMimeTypes = array("image/gif", "image/jpeg", "image/pjpeg", "image/x-png", "image/png", "image/svg+xml"); // Validate image. if (!in_array(strtolower($mimeType), $allowedMimeTypes) || !in_array(strtolower($extension), $allowedExts)) { throw new \Exception("File does not meet the validation."); } // Generate new random name. $name = sha1(microtime()) . "." . $extension; $fullNamePath = dirname(__FILE__) . $fileRoute . $name; // Check server protocol and load resources accordingly. if (isset($_SERVER["HTTPS"]) && $_SERVER["HTTPS"] != "off") { $protocol = "https://"; } else { $protocol = "http://"; } // Save file in the uploads folder. move_uploaded_file($tmpName, $fullNamePath); // Generate response. $response = new \StdClass; $response->link = $protocol.$_SERVER["HTTP_HOST"].dirname($_SERVER["PHP_SELF"]).$fileRoute . $name; // Send response. echo stripslashes(json_encode($response)); } catch (Exception $e) { // Send error response. echo $e->getMessage(); http_response_code(404); } ?>是一个模块，其中有一个具有相同名称（datetime）的类，该类具有类方法datetime。您需要将其称为：

strptime()

或者更改您的导入声明：

dt_start = datetime.datetime.strptime(date1, '%d, %m, %Y')

这样它只会将from datetime import datetime类导入到当前的命名空间。

日期输入格式？

1 个答案: