我从一个例子创建了简单的Spring MVC项目,但它不起作用。我使用Tomcat,它在 WEB-INF / views / 包中看不到我的index.jsp
,我收到404错误。但是如果我将 index.jsp 放入 webapp 包中,Tomcat就会找到它。这是我的配置和类:
的web.xml:
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>WEB-INF/dispatcher-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.form</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
调度-servlet.xml中:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<mvc:annotation-driven />
<mvc:resources mapping="/resources/**" location="/resources/" />
<context:component-scan base-package="com.mihusle" />
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/views/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
MainController:
package com.mihusle.controller;
import com.mihusle.model.User;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.ModelAttribute;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
/**
* Created by MHSL on 17.06.2017.
*/
@Controller
public class MainController {
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView main() {
ModelAndView modelAndView = new ModelAndView();
modelAndView.addObject("userJSP", new User());
modelAndView.setViewName("index");
return modelAndView;
}
@RequestMapping(value = "/check-user")
public ModelAndView checkUser(@ModelAttribute("userJSP") User user) {
ModelAndView modelAndView = new ModelAndView();
modelAndView.setViewName("secondPage");
modelAndView.addObject("userJSP", user);
return modelAndView;
}
}
用户:
package com.mihusle.model;
import org.springframework.stereotype.Component;
/**
* Created by MHSL on 17.06.2017.
*/
@Component
public class User {
private String name;
private String password;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
}
的index.jsp:
<%@ taglib prefix="spring" uri="http://www.springframework.org/tags/form" %>
<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
<body>
<spring:form method="post" modelAttribute="userJSP" action="check-user">
Name: <spring:input path="name"/> (path="" - указывает путь, используемый в modelAttribute=''. в нашем случае User.name) <br/>
Password: <spring:input path="password"/> <br/>
<spring:button>Next Page</spring:button>
</spring:form>
</body>
</html>
请帮忙。我整天都在努力寻找解决方案,但现在我没有假设这里可能存在什么问题。感谢
答案 0 :(得分:-1)
首先,您应该在web.xml
。
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
其次,永远不会,将jsp
或html
个网页放在WEB-INF
文件夹下。它用于包含客户端无法访问的文件。