我有以下数据结构:
不幸的是,' days'不会使用下面的代码从数据库中删除。
我目前的代码:
const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp(functions.config().firebase);
exports.deleteOldItems = functions.database.ref('/path/to/items/{pushId}') //irrelevant to the question
.onWrite(event => {
var ref = event.data.ref.parent; // reference to the items
var now = Date.now();
var cutoff = now - 2 * 60 * 60 * 1000;
var oldItemsQuery = ref.orderByChild('timestamp').endAt(cutoff);
return oldItemsQuery.once('value', function(snapshot) {
// create a map with all children that need to be removed
var updates = {};
snapshot.forEach(function(child) {
updates[child.key] = null
});
// execute all updates in one go and return the result to end the function
return ref.update(updates);
}).then(function() {;
return functions.database.ref('/days').remove(); // /days doesn't get removed!
});
});
答案 0 :(得分:2)
你可以这样做:
let updates = {};
updates['/days'] = null;
firebase.database().ref().update(updates);
请参阅docs;
中的“更新或删除数据”在您的代码中:
.then(function() {;
let updates = {};
updates['/days'] = null;
return firebase.database().ref().update(updates)
});
编辑:尝试以下内容:
const admin = require('firebase-admin');
admin.initializeApp(functions.config().firebase);
const defaultDatabase = admin.database();
...
let updates = {};
updates['/days'] = null;
defaultDatabase.ref().update(updates);