据我所知,矩形的碰撞计算如下:
((a.y + a.height) < (b.top)) ||
(a.y > (b.y + b.height)) ||
((a.x + a.width) < b.x) ||
(a.x > (b.x + b.width))
我希望公式计算两个圆是否发生碰撞。
由于
答案 0 :(得分:1)
计算它们之间的距离。然后,如果距离小于它们的半径之和,则它们会发生碰撞。
答案 1 :(得分:0)
// calculates distance between two points
function distance (p0, p1) {
var dx = p1.x - p0.x,
dy = p1.y - p0.y;
return Math.sqrt(dx * dx + dy * dy);
}
// if the distance between the points is less then or equal to the sum of radii
// it returns true i.e collision else false
function circleCollision (c0, c1) {
return distance(c0, c1) <= c0.radius + c1.radius;
}