如何从codeigniter中的common helper调用任何模型函数

Question

if（！function_exists（'audit'））{         函数addAudit（$ id_user，$ description）         {

        $response_audit = $CI->Audit_model->addAudit($id_user,$description);
        if($response_audit){
            log_message('debug',' Product --addAudit :: Response received from model'); 
            }else{
            log_message('debug',' Product --addAudit :: Response didnot received from model'); 
        }
    }
}

Answer 1

if( !function_exists('audit') ) { 
    function addAudit($id_user,$description) {
                $CI = &get_instance();
                $CI->load->model ( 'Audit_model' );
                $response_audit = $CI->Audit_model->addAudit($id_user,$description);
                if($response_audit){
                    log_message('debug',' Product --addAudit :: Response received from model'); 
                    }else{
                    log_message('debug',' Product --addAudit :: Response didnot received from model'); 
                }
        }

Answer 2

在普通助手的构造函数中：

ul > li